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Anuta_ua [19.1K]
3 years ago
8

Suppose you are navigating a spacecraft far from other objects. The mass of the spacecraft is 2.6 × 104 kg (about 26 tons). The

rocket engines are shut off, and you're coasting along with a constant velocity of <0, 20, 0> km/s. As you pass the location <7, 4, 0> km you briefly fire side thruster rockets, so that your spacecraft experiences a net force of <5 × 105, 0, 0> N for 24.5 s. The ejected gases have a mass that is small compared to the mass of the spacecraft. You then continue coasting with the rocket engines turned off. Where are you an hour later? (Think about what approximations or simplifying assumptions you made in your analysis. Also think about the choice of system: what are the surroundings that exert external forces on your system?)\
Physics
1 answer:
insens350 [35]3 years ago
5 0

56 will be the answer all you do is divide 104 to 26 then divide 2.6

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a bee flies 25m north of the hive, then 10m east, 5m west and 10m south. how far north and east of the hive is it now?
krok68 [10]
(25m north) + (10m south) = 15m north

(10m east) + (5m west) = 5m east

So the bee is now 15m north and 5m east of the hive.
7 0
3 years ago
Read 2 more answers
Action and Reaction are equal in magnitude and opposite in direction.Then,Why do they not balance each other?​
Ivan

Answer:

Newton's third law of motion states that every action has an equal and opposite reaction. This indicates that forces always act in pairs. Reaction forces are equal and opposite, but they are not balanced forces because they act on different objects so they don't cancel each other out.

4 0
2 years ago
Moustapha jones drives east at 100km/hr for 3 hours then back west at 80km/hr for 1.5 hours. which pair of answers gives his ave
olya-2409 [2.1K]

The average speed of the car is 93.33 km/hr and the average velocity of the car is 40 km/hr.

The total distance cover in east direction is=100*3=300 km

The total distance cover in the west direction=80*1.5=120 km

The total distance covered is =300+120=420 km

And Total displacement of the car is =300-120=180 km

As we know that the average speed is given as

Avg Speed =Total Distance / Total time

=420/4.5=93.33 km/hr

As we know that the average velocity is given as

Avg Speed =Total Displacement/ Total time

=180/4.5=40 km/hr

Therefore, The average speed of the car is 93.33 km/hr and the average velocity of the car is 40 km/hr.

7 0
3 years ago
What is the net power needed to change the speed of a 1600-kg sport utility vehicle from 15.0 m/s to 40.0 m/s in 4.00 seconds
Sergio039 [100]

Answer:

The net power needed to change the speed of the vehicle is 275,000 W

Explanation:

Given;

mass of the sport vehicle, m = 1600 kg

initial velocity of the vehicle, u = 15 m/s

final velocity of the vehicle, v = 40 m/s

time of motion, t = 4 s

The force needed to change the speed of the sport vehicle;

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The net power needed to change the speed of the vehicle is calculated as;

P_{net} = \frac{1}{2} F[u + v]\\\\P_{net} = \frac{1}{2} \times 10,000[15 + 40]\\\\P_{net} = 275,000 \ W

3 0
2 years ago
Perfect symmetrical cone type volcanoes would have what type of drainage pattern
Charra [1.4K]

Perfect symmetrical cone type volcanoes would have radial drainage pattern.

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6 0
3 years ago
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