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spin [16.1K]
3 years ago
13

30 POINTS!!!

Chemistry
2 answers:
miv72 [106K]3 years ago
8 0
The answer to this question is <span>HCL. Since pKa = -log[Ka], we have
                                Ka = 10^(-</span><span>pKa)
so with HCL, pKA = -8 and so
                                Ka = 10^(-(-8)) = 10^8
which is a very large Ka value implying full completion of reaction.
</span>
Musya8 [376]3 years ago
4 0
Answer is: HCl (hydrochloric acid) <span>will have the largest amount of conjugate base.

Hydrochloric acid is the strongest acid present in this question, because it has largest Ka value:
pKa(HCl) = -8.
Ka(HCl) = 10</span>∧(-pKa).
Ka(HCl) = 10⁸.
Chemical dissotiation of hydrochloric acid:
HCl(aq) → H⁺(aq) + Cl⁻(aq).
Ka(HCl) = [H⁺]·[Cl⁻] / [HCl].
Concentration of Cl⁻ ions (conjugate base of hydrochloric acid) is very high.
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