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kotegsom [21]
3 years ago
5

What are two elements that form a large number of bonds and that both have similar properties to carbon?

Chemistry
1 answer:
lakkis [162]3 years ago
3 0
Silicon and Germanium. You can conclude it from its position in the periodic table. Silicon and Germanium are in the same group of the Carbon. That implies that all three have the same number of electrons in the outer orbital, which is responsible for the bonds.
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explain how a metal with one valence electron compares with a metal with more than one valence electron
slamgirl [31]

Explanation:

A metal with one valence electron is highly reactive compared to those with more than one electron.

Atoms including those of metals reacts in order attain a stable electronic configuration just like those of noble gases.

An atom with one valence electron have just one electron in its valence shell.

  • Metals generally have large sizes.
  • when the electron in this shell is lost, the metal atom can then attain stability.
  • therefore, such atom will quickly want to combine with any other willing to accept the electron so that they can be stable.
  • Those with more than one electron will find it difficult to lose them.
  • It requires huge energy to remove such electrons compared to the ones with only one valence electron.

learn more:

Valence electrons brainly.com/question/3023499

#learnwithBrainly

7 0
3 years ago
Determining nitrogen balance in the clinical setting can be very valuable. To determine a client’s state of nitrogen balance, a
nikdorinn [45]

Answer:

We also need the nitrogen intake

Explanation:

The nitrogen balance is the difference between the nitrogen intake and nitrogen excreted. If this calculation is positive, the body grow; if it is negative, the body is decreased.

6 0
3 years ago
3. In an experiment it was found that 40.0cm of 0.2M sodium hydroxide solution just neutralized 0.2g
hjlf

The relative molecular mass of acid A : 50 g/mol

<h3>Further explanation</h3>

Given

40.0 cm³(40 ml) of 0.2M sodium hydroxide

0.2g  of a dibasic acid

Required

the relative molecular mass of acid A

Solution

Titration formula

M₁V₁n₁=M₂V₂n₂

n=acid/base valence(number of H⁺/OH⁻)

NaOH ⇒ n = 1

Dibasic acid =  diprotic acid (such as H₂SO₄)⇒ n = 2

mol = M x V

Input the value in the formula :(1 = NaOH, 2=dibasic acid)

0.2 x 40 x 1 = M₂ x V₂ x 2

M₂ x V₂ = 4 mlmol = 4.10⁻³ mol ⇒ mol of Acid A

The relative molecular mass of acid A (M) :

\tt M_A=\dfrac{mass }{mol}=\dfrac{0.2~g}{4.10^{-3}}=50~g/mol

5 0
3 years ago
Identify and name the global<br> wind belts.<br> A<br> B<br> C<br> D<br> E<br> F<br> G
Finger [1]

Answer:

A. Polar Easterlies

B. Westerlies

C. Northeast Trades

D. Southeast Trades

E. Westerlies

F. Polar Easterlies

G. Hadley cell

Explanation:

I am pretty sure this is right. Hope that helps

8 0
3 years ago
What is the density (g/L) of CHCl3 vapor at 1.00 atm and 298 K?
Scrat [10]

Answer:

4.8 g/mL is the density of chloroform vapor at 1.00 atm and 298 K.

4 0
3 years ago
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