Answer:

Explanation:
Equation for the heterogeneous system is given as:
⇄

The concentrations and pressures at equilibrium are:
![[A] = 9.68*10^{-2}M](https://tex.z-dn.net/?f=%5BA%5D%20%3D%209.68%2A10%5E%7B-2%7DM)

![[C]=14.64M](https://tex.z-dn.net/?f=%5BC%5D%3D14.64M)
![[D]=10.11M](https://tex.z-dn.net/?f=%5BD%5D%3D10.11M)

If we convert both pressure into bar; we have:



1 torr = 0.001333 bar

![K=\frac{[P_E]^3}{[A]^2[P_B]^3}](https://tex.z-dn.net/?f=K%3D%5Cfrac%7B%5BP_E%5D%5E3%7D%7B%5BA%5D%5E2%5BP_B%5D%5E3%7D)


Answer :
(1) The number of valence electrons present in the compound is, 20
(2) The number of bonded electrons present in the compound is, 16
(3) The number of lone pair electrons present in the compound is, 4
(4) The number of single bonds present in the compound is, 8
Explanation :
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.
In the Lewis-dot structure the valance electrons are shown by 'dot'.
The given molecule is, 
As we know that carbon has '4' valence electrons, hydrogen has '1' valence electrons and oxygen has '6' valence electrons.
Therefore, the total number of valence electrons in
= 2(4) + 6(1) + 6 = 20
According to Lewis-dot structure, there are 16 number of bonding electrons and 4 number of non-bonding electrons or lone pair of electrons.
The Lewis-dot structure of
is shown below.
Answer:
1. density = 0.89 g/cm3
2. Yes is possible to identify the liquid
3. ethanolamine
Explanation:
<u>Data:</u>
mass = 682 g
volume = 0.767 L = 767 mL or cm3
1.
To calculate the density of the liquid it is necessary to know that the density formula is:

The data obtained is replaced in the formula:

2.
With the given data it is possible to identify the liquid, this because the density value is a basic property of each liquid.
3.
It is possible to determine what liquid it is, since when comparing the value obtained with those reported in the collection of Material Safety Data Sheets (MSOS), the value that agrees is that of ethanolamine.
When answering the above question or problem, <span>first thing to realize is that the dissolution of the Na3PO4 can be written in a format that may be easier to see what is happening here. </span>
<span>Na3PO4 ----> 3 Na(+) + PO4(-3) </span>
<span>Now, you are starting out with a 0.35 M solution of Na3PO4, but when you dissolve the Na3PO4 into solution there are 3 Na(+) ions made for every Na3PO4 molecule that dissolves. Therefore to calculate the concentration of Na(+) ions in the final solution, take 3 times the inital concentration. 0.35 * 3 = 1.05 M in Na(+)</span>
Macro-minerals and trace minerals