What type of cell is lacobacillus
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If dominant allele = p, and recessive allele = q,
and p+q = 1, then:
So if 75% have the p, then p^2 = homozygous dominant
And if the other 25% have the q, the q^2 = homozygous recessive
Now those remaining MUST be the heterozygous, thus 2pq are those:
2pq = 2(.75)(.25) = .375
Therefore homozygous dominant are 56.3% and heterozygous are 37.5%
and p+q = 1, then:
So if 75% have the p, then p^2 = homozygous dominant
And if the other 25% have the q, the q^2 = homozygous recessive
Now those remaining MUST be the heterozygous, thus 2pq are those:
2pq = 2(.75)(.25) = .375
Therefore homozygous dominant are 56.3% and heterozygous are 37.5%