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3 years ago

What does the energy hill represent on an energy diagram?

Chemistry

1 answer:

Butoxors [25]3 years ago

6 0

Answer:

The correct answer is option D.

Explanation:

When a chemical reaction proceeds the reactants are converted into products. The energy hill represents the potential energy of the reaction.

There are two conditions: If the reaction is endothermic than the energy of the products is greater than the energy of the reactants and ΔH is positive. This energy gain is shown in the form of a peak. In an exothermic reaction, the energy of the products is lower than the reactants and ΔH is negative.

So the suitable option is D which states that the reaction is endothermic and the potential energy gained by the products is higher when a reaction proceeds.

You might be interested in

Write the beta decay equation for the following isotope: 91 38 Sr? Please write out steps

babymother [125]

Answer:

$\rm _{38}^{91}Sr \longrightarrow \, _{-1}^{0}e + \, _{39}^{91}Y$

Explanation:

The unbalanced nuclear equation is

$\rm _{38}^{91}Sr \longrightarrow \, _{-1}^{0}e \, + \, ?$

Let's write the question mark as a nuclear symbol.

$\rm _{38}^{91}Se} \longrightarrow \, _{-1}^{0}e \, + \, _{Z}^{A}X$

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.

Then

98 = 0 + A, so A = 98 - 0 = 98, and

38 = -1 + Z, so Z = 38 + 1 = 39

Then, your nuclear equation becomes

$\rm _{38}^{91}Sr \longrightarrow \, _{-1}^{0}e + \, _{39}^{91}X$

Element 39 is yttrium, so the balanced nuclear equation is

$\rm _{38}^{91}Sr \longrightarrow \, _{-1}^{0}e + \, _{39}^{91}Y$

7 0

3 years ago

What do most decomposition reactions require

NikAS [45]

Answer: Most decomposition reactions require an input of energy in the form of heat, light, or electricity. Binary compounds are compounds composed of just two elements. The simplest kind of decomposition reaction is when a binary compound decomposes into its elements.

7 0

3 years ago

Read 2 more answers

Describe two ways in which humans have<br> negatively affected groundwater.

ludmilkaskok [199]

Answer: Stressors

Explanation:

it can deplete aquifers include changes in precipitation and snowmelt patterns

4 0

3 years ago

Refer to the illustration of the periodic table to determine which formula is correct.

Mekhanik [1.2K]

Answer:

D. MgO

Explanation:

We need to look at the charge of element. (Look at a periodic table for this)

Mg, which is Magnesium, has a charge of 2+ because it's in the second column, or group, from the left.

O, which is Oxygen, has a charge of 2- because it's in the second column, or group, from the right.

Since Mg is 2+, it's the cation and since O is 2-, it's the anion. We can put these two elements together into an ionic compound.

Mg^(2+) and O^(2-) becomes Mg2O2, where we can cancel the 2s: MgO.

Thus, the answer is D.

Hope this helps!

5 0

3 years ago

Consider the reaction below for which K = 78.2 atm-1. A(g) + B(g) ↔ C(g) Assume that 0.386 mol C(g) is placed in the cylinder re

borishaifa [10]

Answer:

1.65 L

Explanation:

The equation for the reaction is given as:

A + B ⇄ C

where;

numbers of moles = 0.386 mol C (g)

Volume = 7.29 L

Molar concentration of C = $\frac{0.386}{7.29}$

= 0.053 M

A + B ⇄ C

Initial 0 0 0.530

Change +x +x - x

Equilibrium x x (0.0530 - x)

$K = \frac{[C]}{[A][B]}$

where

K is given as ; 78.2 atm-1.

So, we have:

$78.2=\frac{[0.0530-x]}{[x][x]}$

$78.2= \frac{(0.0530-x)}{(x^2)}$

$78.2x^2= 0.0530-x$

$78.2x^2+x-0.0530=0$

Using quadratic formula;

$\frac{-b+/-\sqrt{b^2-4ac} }{2a}$

where; a = 78.2 ; b = 1 ; c= - 0.0530

= $\frac{-b+\sqrt{b^2-4ac} }{2a}$ or $\frac{-b-\sqrt{b^2-4ac} }{2a}$

= $\frac{-(1)+\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}$ or $\frac{-(1)-\sqrt{(1)^2-4(78.2)(-0.0530)} }{2(78.2)}$

= 0.0204 or -0.0332

Going by the positive value; we have:

x = 0.0204

[A] = 0.0204

[B] = 0.0204

[C] = 0.0530 - x

= 0.0530 - 0.0204

= 0.0326

Total number of moles at equilibrium = 0.0204 + 0.0204 + 0.0326

= 0.0734

Finally, we can calculate the volume of the cylinder at equilibrium using the ideal gas; PV =nRT

if we make V the subject of the formula; we have:

$V = \frac{nRT}{P}$

where;

P (pressure) = 1 atm

n (number of moles) = 0.0734 mole

R (rate constant) = 0.0821 L-atm/mol-K

T = 273.15 K (fixed constant temperature )

V (volume) = ???

$V=\frac{(0.0734*0.0821*273.15)}{(1.00)}$

V = 1.64604

V ≅ 1.65 L

3 0

3 years ago