On the left side. The alkali metals are group 1, the alkaline earth metals are group 2, and the transition metals are groups 3-12.
CO + 2 H2 → CH3OH
<span> find # of mols in each reactants, </span>
<span>152500 g CO x 1 mol CO / 28.01g CO = 5444 mol CO </span>
<span>24500 g H2 x 1 mol H2 / 2.02 g H2 = 12129 mol H2 </span>
<span>mol ratio between CO and H2 is 1:2, which means each mol of production of CH3OH need 1 mol of CO and 2 mol of H. </span>
<span>H2 is enough to produce 6064 mols of CH3OH but there are only 5444mol of CO. </span>
<span>5444 mol CH3OH x molar mass of CH3OH / 1 mol CH3OH </span>
<span>= 174371 g = 174.4 kg</span>
Answer: SO2(Sulfur Dioxide) Molecular Geometry & Lewis Structure
Explanation: So2Molecular Geometry
We know that the shape which minimizes the repulsions of electronics pairs is adopted by the molecule to form the structure. The molecular shape of SO2 is same as the molecular geometry of Carbon Dioxide (CO2). We will show the bonding of SO2 without making assumption below.
O =S =O
D. Ca (oh)2 (calcium hydroxide)
Answer:
HgSO₄
Explanation:
% => g => moles => ratio => reduce => empirical ratio
%Hg = 67.6% => 67.6g/201g/mol = 0.34mol
%S = 10.8% => 10.8g/32g/mol = 0.34mol
%O = 21.6% => 21.6g/16g/mol = 1.35mol
Hg:S:O => 0.34:0.34:1.35
Reduce to whole number ratio by dividing by the smaller mole value...
Hg:S:O => 0.34/.34:0.34/.34:1.35/.34 => Empirical Ratio = 1:1:4
∴ Empirical Formula is HgSO₄