Answer:
Ionic compounds
Explanation:
Molecular formula consists of chemical symbols for constituent elements followed by the numeric subscripts describing number of the atoms of each element present in one molecule of the compound.
On the other hand, ionic compounds do not exist in the form of molecules. They are in the form of crystal lattice in the solid state which contains many ions each of cation and anion.
<u>Thus, a ionic compounds are unable to write a molecular formula. Empirical formulas to used to represent them.</u>
Answer:
Carbonyl
Explanation:
While the diagram is slightly unclear, the molecule most likely being shown is a carbonyl. A molecule is a carbonyl when there is a carbon double-bonded to an oxygen.
Answer:
See below.
Step-by-step explanation:
Ethers react with HI at high temperature to produce an alky halide and an alcohol.
R-OR' + HI ⟶ R-I + H-OR'
<em>Benzylic ethers</em> react by an Sₙ1 mechanism by forming the stable benzyl cation.
- PhCH₂-OR + HI ⟶ PhCH₂-O⁺(H)R + I⁻ Protonation of the ether
- PhCH₂-O⁺(H)R ⟶ PhCH₂⁺ + HOR Sₙ1 ionization of oxonium ion
- PhCH₂⁺ + I⁻ ⟶ PhCH₂-I Nucleophilic attack by I⁻
If there is excess HI, the alcohol formed in Step 2 is also converted to an alkyl iodide:
ROH +HI ⟶ R-I + H-OH
Thus, benzyl ethyl ether reacts to form benzyl iodide (a) and ethanol (b).
The ethanol reacts with excess HI in an Sₙ2 reaction to form ethyl iodide (c).
The answer would be decomposers
We can use the following equation to calculate the concentration of diluted solution.
c1v1 = c2v2
where c1 is concentration and v1 is volume of stock solution, which is the more concentrated solution.
c2 is concentration and v2 is the volume of diluted solution.
substituting the values in the equation,
0.188 M x 25.0 mL = c2 x 150.0 mL
c2 = 0.0313 M
concentration of diluted solution is 0.0313 M
