Answer:
Lithium
Explanation:
Alkali metals are group of metals which are present in first group of periodic table. As we know atomic number is equal to number of protons contained by a particular element. Therefore, the alkali metals along with there number of protons are listed below;
Alkali Metal Number of Protons
Lithium 3
Sodium 11
Potassium 19
Rubidium 37
Cesium 55
Francium 87
Hence, it is cleared from above table that Lithium is having fewer protons than 10.
Answer:
The ration of the molar solubility is 165068.49.
Explanation:
The solubility reaction of the magnesium hydroxide in the pure water is as follows.

![[Mg^{2+}][OH^{-}]](https://tex.z-dn.net/?f=%5BMg%5E%7B2%2B%7D%5D%5BOH%5E%7B-%7D%5D)
Initial 0 0
Equili +S +2S
Final S 2S
![K_{sp}=[Mg^{2+}][OH^{-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BMg%5E%7B2%2B%7D%5D%5BOH%5E%7B-%7D%5D)


Solubility of
in 0.180 M NaOH is a follows.

![[Mg^{2+}][OH^{-}]](https://tex.z-dn.net/?f=%5BMg%5E%7B2%2B%7D%5D%5BOH%5E%7B-%7D%5D)
Initial 0 0
Equili +S +2S
Final S 2S+0.180M
![K_{sp}=[Mg^{2+}][OH^{-}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%3D%5BMg%5E%7B2%2B%7D%5D%5BOH%5E%7B-%7D%5D)



Therefore, The ration of the molar solubility is 165068.49.
The answer for the following problem is mentioned below.
- <em><u>Therefore the mass of an object is 14.16 grams.</u></em>
Explanation:
Force:
The push or pull on an object with mass that cause change in the velocity
It is a vector quantity.
The formula to calculate the force is:
F = m × a
Given:
Force (F) = -136 N
acceleration (a) = -9.6 m/s^2
To calculate:
mass of the object (m)
We know that,
<em>F = m × a</em>
where,
F represents the force of the object
m represents mass of an object
a is acceleration of an object
From the equation;
-136 = m × -9.6
m = 
m = 14.16 grams
<em><u>Therefore the mass of an object is 14.16 grams.</u></em>
Divide by 1000
145÷1000=0.145
Hope this will be helpful.
Answer:
Evaporated via combustion.
Explanation:
The loss on ignition (LOI) and Ash content are inorganic analytical techniques used to determine the percentage by mass of hydrocarbon in compounds. This process allows volatile matter and possibly impurities found in a material to evaporate, leaving behind the true chemical constituents of the material.
The 10kg lost could be moisture content of the tree, or other volatile matter which has escaped on combustion of the tree.