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Anna11 [10]
3 years ago
5

How many mg of calcium are present in a 500-mg tablet of calcium carbonate?​?

Chemistry
1 answer:
Setler79 [48]3 years ago
3 0

The molar mass of calcium carbonate is 100 mg/mmol, so the number of moles is:

moles CaCO3 = 500 mg / (100 mg/mmol) = 5 mmol

We see that there is 1 mole of Ca per 1 mole of CaCO3, therefore:

<span>mass Ca = 5 mmol * (40.08 mg/mmol) = 200.22 mg</span>

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