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Elenna [48]
3 years ago
14

A 8.96-L sample of gas has a pressure of 1.86 atm and a temperature of 94 °C. The sample is allowed to expand to a volume of 11.

5 L and is cooled to 43 °C. Calculate the new pressure of the gas, assuming that no gas escaped during the experiment.
Chemistry
1 answer:
Varvara68 [4.7K]3 years ago
8 0

Answer:

Explanation:

Explanation:

All you have to do here is use the ideal gas law equation, which looks like this

P

V

=

n

R

T

−−−−−−−−−−

Here

P

is the pressure of the gas

V

is the volume it occupies

n

is the number of moles of gas present in the sample

R

is the universal gas constant, equal to

0.0821

atm L

mol K

T

is the absolute temperature of the gas

Rearrange the equation to solve for

T

P

V

=

n

R

T

⇒

T

=

P

V

n

R

Before plugging in your values, make sure that the units given to you match those used in the expression of the universal gas constant.

In this case, the volume is given in liters and the pressure in atmospheres, so you're good to go.

Plug in your values to find

T

=

3.10

atm

⋅

64.51

L

9.69

moles

⋅

0.0821

atm

⋅

L

mol

⋅

K

T

=

251 K

−−−−−−−−−

The answer is rounded to three

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Please help quick
Rama09 [41]

Answer:

c = 0.898 J/g.°C

Explanation:

1) Given data:

Mass of water = 23.0 g

Initial temperature = 25.4°C

Final temperature = 42.8° C

Heat absorbed = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Specific heat capacity of water is 4.18 J/g°C

ΔT = 42.8°C - 25.4°C

ΔT = 17.4°C

Q = 23.0 g ×  × 4.18 J/g°C × 17.4°C

Q = 1672.84 j

2) Given data:

Mass of metal = 120.7 g

Initial temperature = 90.5°C

Final temperature = 25.7 ° C

Heat released = 7020 J

Specific heat capacity of metal = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 25.7°C - 90.5°C

ΔT = -64.8°C

7020 J = 120.7 g ×  c ×  -64.8°C

7020 J = -7821.36 g.°C ×  c

c = 7020 J / -7821.36 g.°C

c = 0.898 J/g.°C

Negative sign shows heat is released.

7 0
3 years ago
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