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castortr0y [4]
2 years ago
11

Diagram of simple cell and dry cell

Physics
1 answer:
Dennis_Churaev [7]2 years ago
6 0

Answer:

Please see the file attached

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How to find net horizontal force with friction and applied force?
wlad13 [49]
Just subtract the both of them.  
7 0
4 years ago
What is used to make a cast of a tool mark ?
KatRina [158]
silicone rubber is used to make a cast of a tool mark.
8 0
3 years ago
Waldo gets stopped by the police, and the police officer tells Waldo that she caught him on radar doing 50 miles per hour in a 4
sergij07 [2.7K]

Answer:

He calculated his average speed.

Explanation:

Waldo calculated an average of his speed in 2 hours rather than his speed whilst driving which means instead of doing 50/1 hour = 50 mph, he did 50/2hours which is how he got 25 mph. Hope this helps!

5 0
3 years ago
Read 2 more answers
A person with normal vision can focus on objects as close as a few centimeters from the eye up to objects infinitely far away. T
NeTakaya

Answer:

a)   f₁ = 3.50 m ,  b)     f₂ = 0.84 m  

Explanation:

For this exercise we must use the constructor equation

          1 / f = 1 / p + 1 / q

where f is the focal length, p is the distance to the object and q is the distance to the image

a) the distance where the image should be placed is q = 3.50 m and the object is located at infinity p = ∞

           1 / f₁ = 1 /∞ + 1 / 3.50

           f₁ = 3.50 m

b) in this case the image is at q = -0.600 m and the object p = 0.350 m

           1 / f₂ = 1 / 0.350 -1 / 0.600

the negative sign, is because the image is in front of the object

           1 / f₂ = 1,1905

            f₂ = 1 / 1,1905

            f₂ = 0.84 m

3 0
4 years ago
One star (star A) has a parallax of 3.4 arc seconds, while a second star (star B) has a parallax of 1.70 arc seconds. What can y
Alchen [17]

Based of the distance of each star, we can conclude that Star A must have a larger proper motion than Star B.

The given parameters;

  • parallax of star A = 3.4 arc seconds
  • parallax of star B = 1.7 arc seconds

The distance of each star form a Parallax is calculated as

d = \frac{1}{p}

Where;

d is the distance to star, [parsecs]

p is parallax, [arc seconds]

The distance of star A;

d = \frac{1}{3.4} = 0.3 \ parsecs

The distance of start B;

d = \frac{1}{1.7} = 0.6 \ parsecs

On average, it is known that a nearby star will have a large proper motion.

Based on the distance of each star calculated above, star A is nearer and it will have a larger proper motion that star B.

Learn more here: brainly.com/question/13046296

4 0
3 years ago
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