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3 years ago

When you don't have enough room to stop, you may _______ to avoid what's in front of you.

Physics

2 answers:

Natalka [10]3 years ago

8 0

When you don't have enough room to stop, you may steer away to avoid what's in front of you.

xxMikexx [17]3 years ago

7 0

Do you have the options? I would say swerve?

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A rocket, initially at rest on the ground, accelerates straight upward from rest with constant (net) acceleration 29.4 m/s2 m /

Sidana [21]

Answer:

The maximum height is 2881.2 m.

Explanation:

Given that,

Acceleration = 29.4 m/s²

Time = 7.00 s

We need to calculate the distance

Using equation of motion

$s=ut+\dfrac{1}{2}at^2$

Put the value into the formula

$s=0+\dfrac{1}{2}\times29.4\times7^2$

$s=720.3\ m$

We need to calculate the velocity

Using formula of velocity

$v=a\times t$

Put the value into the formula

$v=29.4\times7$

$v=205.8\ m/s$

We need to calculate the height

Using formula of height

$H=\dfrac{v^2}{2g}$

Put the value into the formula

$H=\dfrac{(205.8)^2}{2\times9.8}$

$H=2160.9\ m$

We need to calculate the maximum height

Using formula for maximum height

$H'=H+s$

Put the value into the formula

$H'=2160.9+720.3$

$H'=2881.2\ m$

Hence, The maximum height is 2881.2 m.

4 0

3 years ago

Scientific observations should be reported with bias as long as they benefit a scientist's employer

Ira Lisetskai [31]

False, there are always pros and cons to research

8 0

3 years ago

Water, which we can treat as ideal and incompressible, flows at 12 m/s in a horizontal pipe with a pressure of 3.0 × 10^4 Pa.

Triss [41]

Answer:

9.8 × 10⁴Pa

Explanation:

Given:

Velocity V₁ = 12m/s

Pressure P₁ = 3 × 10⁴ Pa

From continuity equation we have

ρA₁V₁ = ρA₂V₂

A₁V₁ = A₂V₂

making V₂ the subject of the equation;

$V_{2} = \frac{A_{1}V_{1}}{A_{2}}$

the pipe is widened to twice its original radius,

r₂ = 2r₁

then the cross-sectional area A₂ = 4A₁

⇒ $V_{2}= \frac{A_{1}V_{1}}{4A_{1}}$

$V_{2}= \frac{V_{1}}{4}$

This implies that the water speed will drop by a factor of $\frac{1}{4}$ because of the increase the pipe cross-sectional area.

The Bernoulli Equation;

Energy per unit volume before = Energy per unit volume after

p₁ + $\frac{1}{2}$ ρV₁² + ρgh₁ = p₂ + $\frac{1}{2}$ ρV₂² + ρgh₂

Total pressure is constant and $P_{T}$ = P = $\frac{1}{2}$ ρV₂²ρV²

p₁ + $\frac{1}{2}$ ρV₁² = p₂ + $\frac{1}{2}$ ρV₂²

Making p₂ the subject of the equation above;

p₂ = p₁ + $\frac{1}{2}$ ρV₁² - $\frac{1}{2}$ ρV₂²

But $V_{2} = \frac{V_{1}}{4}$ so,

p₂ = p₁ + $\frac{1}{2}$ ρV₁² - $\frac{1}{2}$ ρ $\frac{V_{1}^{2}}{4^{2}}$

p₂ = 3.0 x 10⁴ + ( $\frac{1}{2}$ × 1000 × 12²) - ( $\frac{1}{2}$ × 1000 × 12²/4² )

P₂ = 3.0 x 10⁴ + 7.2 × 10⁴ - 4.05 x 10³

P₂ = 9.79 × 10⁴Pa

P₂ = 9.8 × 10⁴Pa

4 0

3 years ago

What type of current is produced by a battery?

padilas [110]

The positive plate is made of lead grid with a lead oxide paste coating and the negative plate is porous lead. Dilute sulphuric acid is the electrolyte. The lead acid battery produced a direct current or DC during a chemical reaction that turns lead dioxide to lead sulphate and sulphuric acid to water.

8 0

3 years ago

It would take almost 2 years for the fastest human-made spacecraft to travel from earth to europa. about how long would it take

worty [1.4K]

First, we need the distance of Europe and Wolf-359 from Earth.
- The distance of Europe from Earth is: $d_E = 6.28 \cdot 10^8 km$
- The distance of Wolf-359 from Earth is instead 7.795 light years. However, we need to convert this number into km. 1 light year is the distance covered by the light in 1 year. Keeping in mind that the speed of light is $c=3 \cdot 10^8 m/s$ , and that in 1 year there are
365 days x 24 hours x 60 minutes x 60 seconds = $3.154 \cdot 10^7 s/y$ , the distance between Wolf-359 and Earth is
$d_W = 7.995 ly\cdot3\cdot 10^8 m/s \cdot 3.154 \cdot 10^7 s=7.38 \cdot 10^{16}m=7.38 \cdot 10^{13}km$

Now we can calculate the time the spaceship needs to go to Wolf-359, by writing a simple proportion. In fact, we know that the spaceship takes 2 years to cover $d_E$ , so
$2 y:d_E = x:d_W$
from which we find $x$ , the time needed to reach Wolf-359:
$x= \frac{2 y\cdot d_W}{d_E}=2.35 \cdot 10^5 years$

4 0

3 years ago