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4 years ago

Which one of these complementary base pairs can form three hydrogen bonds?

Chemistry

1 answer:

ValentinkaMS [17]4 years ago

7 0

Answer:

Option D is the correct answer

Explanation:

There are three hydrogen bonds formed between Guanine and Cytosine base.

The first hydrogen bond is formed between the oxygen atom on Carbon-6 (C-6) of guanine, and one of the hydrogen atoms attached to the Nitrogen atom (i.e the one of the hydrogen atoms in the amino group) on the Carbon-4 (C-4)of the cytosine base.

The second hydrogen bond is formed between the hydrogen atom on Nitrogen-1 (N-1) of the guanine base and Nitrogen-3 (N-3) of the cytosine base.

The third hydrogen bond exist between one of the hydrogen atoms in the amino group attached to the second Carbon (C-2) of the guanine base, and the oxygen atom attached to the second Carbon (C-2) of the cytosine base.

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A certain box contains 200 particles of an ideal gas. how many times more likely is it to find the particles evenly split betwee

Strike441 [17]

Each particle has two possibilities: either it is on the left hand side or it is on the right hand side.

The probability of having them equally split is

P(100,100) = 200C100 / 2^200

where 200C100 is the binomial coefficient.

For the uneven distribution we have

P= 2 * 200C160 / 2^200

where the factor 2 comes in because we could have 160/40 or 40/160 as a division.

So the ratio of probabilities is

200C100 /(2 * 200C160 )

= 2.2 * 10^16

Hope this helps!

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3 years ago

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grigory [225]

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4 years ago

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How many particles are present in 8.0 moles of silver?

Zielflug [23.3K]

Answer:the answer is b

Explanation:I took the test and got it right

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3 years ago

A factor that keeps a population size from growing too large is called a ______ _______.

Liula [17]

Answer:

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7 0

3 years ago

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Assume the hydrolysis of ATP proceeds with ΔG′° = –30 kJ/mol. ATP + H2O → ADP + Pi Which expression gives the ratio of ADP to AT

Andru [333]

Answer:

$6.14\cdot 10^{-6}$

Explanation:

Firstly, write the expression for the equilibrium constant of this reaction:

$K_{eq} = \frac{[ADP][Pi]}{ATP}$

Secondly, we may relate the change in Gibbs free energy to the equilibrium constant using the equation below:

$\Delta G^o = -RT ln K_{eq}$

From here, rearrange the equation to solve for K:

$K_{eq} = e^{-\frac{\Delta G^o}{RT}}$

Now we know from the initial equation that:

$K_{eq} = \frac{[ADP][Pi]}{ATP}$

Let's express the ratio of ADP to ATP:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}}$

Substitute the expression for K:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}} = \frac{[Pi]}{e^{-\frac{\Delta G^o}{RT}}}$

Now we may use the values given to solve:

$\frac{[ADP]}{[ATP]} = \frac{[Pi]}{K_{eq}} = \frac{[Pi]}{e^{-\frac{\Delta G^o}{RT}}} = [Pi]e^{\frac{\Delta G^o}{RT}} = 1.0 M\cdot e^{\frac{-30 kJ/mol}{2.5 kJ/mol}} = 6.14\cdot 10^{-6}$

7 0

4 years ago