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crimeas [40]
3 years ago
8

Changing the number of _____ would change an atom into an atom of a different element

Chemistry
2 answers:
Kamila [148]3 years ago
8 0
Electrons - each atom has its own unique #
Marta_Voda [28]3 years ago
4 0
Changing the number or protons would change the element is an element loses an electron it becomes an ion but if it loses a proton the element its self-changes
eg. calcium has 20 protons if it loses on it becomes potassium that has 19 protons.

Hope that helps :)
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The number of protons in the nucleus of the atom, I believe.  c:
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Use the given figure to complete the statement below.
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Vertical now I need to fill 20 characters
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What is the appropriate chemical formula for Iron(III) Sulfate? Sulfate is SO_4^2 Fe3SO4 O a . Fe2(SO4)3 O b. O c. Fe2SO4 O d. F
AnnyKZ [126]

<u>Answer:</u> The chemical formula of Iron (III) sulfate is Fe_2(SO_4)_3

<u>Explanation:</u>

Iron is the 26th element of periodic table having electronic configuration of [Ar]3d^64s^2.

To form Fe^{3+} ion, this element will loose 3 electrons.

Sulfate ion is a polyatomic ion having chemical formula of SO_4^{2-}

By criss-cross method, the oxidation state of the ions gets exchanged and they form the subscripts of the other ions. This results in the formation of a neutral compound.

So, the chemical formula for Iron (III) sulfate is Fe_2(SO_4)_3

4 0
3 years ago
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Darya [45]

your answer is B my friend


5 0
3 years ago
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A solution with a pH = 13 has approximately how many moles of OH– ions per liter?
GuDViN [60]

Answer :

(A) The number of moles of OH^- ions per liter is, 0.1 moles/L

(B) The number of molecules of H^+ ion is, 6.022\times 10^{10}

(C) The pH of the solution will be, 4

<u>Solution for part A :</u>

First we have to calculate the pOH of the solution.

As we know that,

pH+pOH=14\\\\13+pOH=14\\\\pOH=1

Now we have to calculate the moles of OH^- ion per liter.

pOH=-\log [OH^-]\\\\1=-\log [OH^-]

[OH^-]=0.1moles/L

<u>Solution for part B :</u>

First we have to calculate the H^+ ion concentration.

pH=-\log [H^+]\\\\13=-\log [H^+]

[H^+]=10^{-13}moles/L

Now we have to calculate the number of molecules of H^+ ion

As, 1 mole contains 6.022\times 10^{23} number of molecules of H^+ ion

So, 10^{-13} moles contains 6.022\times 10^{23}\times 10^{-13}=6.022\times 10^{10} number of molecules of H^+ ion

<u>Solution for part C :</u>

pH=-\log [H^+]\\\\pH=-\log (1\times 10^{-4})

pH=4

6 0
3 years ago
Read 2 more answers
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