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Slav-nsk [51]
3 years ago
11

Identify the combustion reaction. c4h12 + 7o2 ⟶ 6h2o + 4co2 2h2 + o2 ⟶ 2h2o al2s3 ⟶ 2al + 3s cl2 + 2kbr ⟶ 2kcl + br2

Chemistry
1 answer:
Levart [38]3 years ago
3 0
From the given equations, the combustion reaction is;
C₄H₁₂ + 7O₂ --> 4CO₂ + 6H₂O
Combustion reactions are when organic compounds react with O₂ to produce water and CO₂. From the given reactions, C₄H₁₂ is an organic compound that reacts with O₂ to produce water and CO₂.
Therefore this is the only reaction that follows the general equation for combustion.
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Atoms of Ca and S would be expected to react in a ratio of<br> A) 1:1<br> B) 1:2<br> C)2:1<br> D)3:1
VMariaS [17]

Answer:

Option A = 1:1

Explanation:

The atoms of calcium and sulphur when react their ration is 1:1. The charge on calcium is +2 and on sulphur is -2.

Ca⁺²S⁻²

The +2 and -2 charges are cancel out and overall charge will be zero.

CaS

so their atomic ratio will be 1:1

7 0
3 years ago
Which of the following would be the best object for stirring hot liquids? (1 point)
MakcuM [25]
A Wooden Spoon is your answer because metal attracts heat more, so it would get hotter.

The wooden spoon would not, so you would use that.

Glad I could help, and good luck!

6 0
4 years ago
Read 2 more answers
Which of the following statements regarding alpha particles are true? Check all that apply.a. Alpha particles have a mass number
egoroff_w [7]

Answer:

The only true statement is:

  • a. <u><em>Alpha particles have a mass number of 4</em></u>

Explanation:

<em>Alpha particles</em> are radiactive particles equivalent to a helium nucleus, so they have two protons and two neutrons.

Hence, alpha particles, α, are represented as:

  • ⁴₂He

The superscript 4 to the left of the chemical symbol is the <em>mass number:</em> 2 protons + 2 neutrons = 4

The subscript 2 to the left of the chemical symbol is the atomic number: 2 protons = 2.

Hence, the statement "a. Alpha particles have a mass number of 4" is true.

As for the other statements, you have:

<em>b. Alpha particles have a nulear charge of +1:</em> <u>false</u>

Since, these particles are the nucleous of the helium atom, the nuclear charge equals the number of protons of this atom: +2. Hence, the statement is false.

c. <em>Alpha particle formation is accompanied by the conversion of a proton into a neutron</em> and d. <em>Alpha particle formation is accompanied by the conversion of a neutron into a proton</em>. <u>(both false</u>)

The conversion of a protons into a neutrons and the conversion of a neutron into a proton are product of other kind of radiactive desintegrations.

  • The conversion of a proton into a neutron involves the emission of a positron ( particle with same mass as the electron but positive charge) from the nucleus, which is represented as ⁰₊₁β.

  • The conversion of a neutron into a proton involves the emssion of an electron from the nucleus, which is the emission of a beta particle represented as ⁰₋₁β.

Therefore, these last two statements are also false.

4 0
3 years ago
Jerod used a golf club to hit a ball what was the action and reaction
Triss [41]
The action was him hitting the ball the reaction was the ball moving after being hit
6 0
3 years ago
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You have a solution of 600 mg of caffeine dissolved in 100 mL of water. The partition coefficient for aqueous caffeine extracted
klio [65]

Answer:

159 mg caffeine is being extracted in 60 mL dichloromethane

Explanation:

Given that:

mass of caffeine in 100 mL of water =  600 mg

Volume of the water = 100 mL

Partition co-efficient (K) = 4.6

mass of caffeine extracted = ??? (unknown)

The portion of the DCM = 60 mL

Partial co-efficient (K) = \frac{C_1}{C_2}

where; C_1= solubility of compound in the organic solvent and C_2 = solubility in aqueous water.

So; we can represent our data as:

K=(\frac{A_{(g)}}{60mL} ) ÷ (\frac{B_{(mg)}}{100mL} )

Since one part of the portion is A and the other part is B

A+B = 60 mL

A+B = 0.60

A= 0.60 - B

4.6=(\frac{0.6-B(mg)}{60mL} ) ÷ (\frac{B_{(mg)}}{100mL})

4.6 = \frac{(\frac{0.6-B(mg)}{60mL} )}{(\frac{B_{(mg)}}{100mL})}

4.6 × (\frac{B_{(mg)}}{100mL}) = (\frac{0.6-B(mg)}{60mL} )

4.6 B *\frac{60}{100} = 0.6 - B

2.76 B = 0.6 - B

2.76 + B = 0.6

3.76 B = 0.6

B = \frac{0.6}{3.76}

B = 0.159 g

B = 159 mg

∴ 159 mg caffeine is being extracted from the 100 mL of water containing 600 mg of caffeine with one portion of in 60 mL dichloromethane.

4 0
3 years ago
Read 2 more answers
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