3 years ago

A vertical spring has a spring constant of

1 answer:

8 0

Hookes law states F=kX where F is the force applied, k is the spring constant, and X is the extension of the spring from its resting point.

Substituting the values in, we get:

F=100*(0.65-0.5)=100*0.15=15N

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A girl pushes a wagon at constant velocity. If the

denpristay [2]

Answer; 100 m/s
Explanation;
F= ma
50 kg x 2 m/s

8 0

3 years ago

Consider burning paper and making a pie. Why would these actions be classified as chemical changes?

Dmitry [639]

they are irreversible (you can't unburn paper) and affect the chemical composition of the object (when paper burns, it transforms the nearby oxygen into carbon dioxide using the carbon in the paper)

3 0

3 years ago

An element's atomic number is 7. How many electrons would an atom of this element have?

almond37 [142]

Hey There!

The atomic number represents the electrons and protons, therefore, if the atomic number of the element is 7 then there are 7 electrons and protons in the element.

In order to determine the amount of neutrons, you would subtract the atomic number from the atomic mass.

Hope this helped!

5 0

4 years ago

I need help if anybody is in physics

Greeley [361]

Explanation:

A B to c I'm gurzsibg it q corenticle question

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3 years ago

How large must the coefficient of static friction be between the tires and the road if a car is to round a level curve of radius

Korvikt [17]

Answer:

<h2>The coefficient of static friction will be 0.7</h2>

Explanation:

Given data

the radius of curve= 90m

speed v= 90 km/h to m/s = (90*100)/60*60= 25 m/s

we know that the expression for the centripetal force acting on the car

$Fc= \frac{mv^2}{r}$ -------1

we also know that the expression for the frictional force between road and tire.

Ff= μmg--------2

Equating equation 1 and 2 we have

μmg= mv^2/r

μ= v^2/gr

substituting the values of speed and radius we have (assuming g= 9.81m/s^2)

μ= 25^2/9.81*90

μ= 625/882.9

μ= 0.7

4 0

3 years ago