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4 years ago

An element's atomic number is 7. How many electrons would an atom of this element have?

Physics

1 answer:

almond37 [142]4 years ago

5 0

Hey There!

The atomic number represents the electrons and protons, therefore, if the atomic number of the element is 7 then there are 7 electrons and protons in the element.

In order to determine the amount of neutrons, you would subtract the atomic number from the atomic mass.

Hope this helped!

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What is the mass number of the isotope lithium-7?

NNADVOKAT [17]

<span>the answer is 7...What is the mass number of the isotope lithium-7? the mass of isotope lithium-7 is 7. </span>

5 0

3 years ago

Read 2 more answers

A standard gold bar stored at Fort Knox, Kentucky, is 7.00 inches long, 3.63 inches wide, and 1.75 inches tall. Gold has a densi

Liula [17]

Answer:

14.1 kg

Explanation:

Given:

Length=7.00inches

Width=3.63 inches

Height=1.75 inches

density = 19,300 kg/m3.

We can convert the given parameters to metre for unit consistency

But we know 1 inches= 0.0254 metre

✓Then Length l=7.00inches

=7×0.0254 metre=0.1778m

✓Width w =3.63 inches

==3.63 ×0.0254 metre=0.092m

✓Height h =1.75 inches

=1.75 ×0.0254 metre=0.0445 m

But Mass= density × volume

Volume= Length× width×height

Mass= density× Length× width×height

= 19300kg/m³×0.1778×0.0922×0.0445

=14.1 kg

Therefore, the mass of the gold bar is 14.1 kg

4 0

3 years ago

An object has a mass of 20 grams and a volume of 5 cubic centimeters what is the object density

Solnce55 [7]

20 g / 5 cm^3 = 4 g/cm^3 or 4000 kg / m^3.

3 0

3 years ago

An object is acted upon by the forces F1equalsleft angle12,7,2right angle and F2equalsleft angle0,4,8right angle. Find the f

Umnica [9.8K]

Answer:

$F_3=(-12,-11,-10)$

Explanation:

It is given that,

Force, $F_1=(12,7,2)$

Force, $F_2=(0,4,8)$

We need to find the force F₃ that must act on the object so that the sum of the forces is zero. Let $F_3=(x,y,z)$

According to question, $F_1+F_2+F_3=0$

$(12,7,2)+(0,4,8)+(x,y,z)=0$

$(12+x)+(11+y)+(10+z)=0$

Since, 12 + x = 0, 11 + y = 0 and 10 + z = 0

The third force is equal to,

$F_3=(-12,-11,-10)$

Hence, this is the required solution.

4 0

3 years ago

1. You and a friend are spending the weekend making up missed lab experiments. You are on to second semester material and are st

goldenfox [79]

Answer:

D) ¼ as large

Explanation:

The magnitude of the electric force between two charges is

$F=k\frac{q_1 q_2}{r^2}$

where

k is the Coulomb's constant

q1 and q2 are the magnitudes of the two charges

r is the separation between them

From the formula we see that the magnitude of the force is inversely proportional to the square of the distance.

In this problem, the distance is doubled:

$r'=2r$

So the new force will be

$F'=k\frac{q_1 q_2}{(2r)^2}=\frac{1}{4}k\frac{q_1 q_2}{r^2}=\frac{1}{4}F$

So the force will decrease to 1/4 of its original value.

8 0

4 years ago