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iren [92.7K]
3 years ago
15

If a species experiences a helpful mutation, like camouflage, explain how that mutation would help the species to better survive

and flourish. Again, be sure to explain how and why that mutation would be helpful.
Help me please I need it fast, I’ll give b if correct!!!

Links = reported

Wrong answer= report (depends if it’s a whole different answer)
Physics
1 answer:
ExtremeBDS [4]3 years ago
4 0

Answer:

A helpful mutation like camoflage would immensely help a species survive and flourish. The reason being the appliances of such a mutation. Camoflage is one of the most apllicable of abilities. It can be used as a defense mechanism, to hide in plain sight, it can be used offensively to avoid being seen while hunting and it can even be used as a form of communication between the species. All of these appliances would greatly benefit the species and would most definitely help it survive and flourish.

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A woman is standing in the ocean, and she notices that after a wave crest passes by, five more crests pass in a time of 50.2 s.
lorasvet [3.4K]

Explanation:

(a) The period of a wave is the time required for one complete cycle. In this case, we have the time of five cycles. So:

T=\frac{t}{n}\\\\T=\frac{50.2s}{5}\\T=10.04s

(b) The frequency of a wave is inversely proportional to its period:

f=\frac{1}{T}\\f=\frac{1}{10.04s}\\f=0.01Hz

(c) The wavelength is the distance between two successive crests, so:

\lambda=30.2m

(d) The speed of a wave is defined as:

v=f\lambda\\v=(0.1Hz)(30.2m)\\v=3.02\frac{m}{s}

8 0
3 years ago
In any homogeneous medium, the constant factor is a wave's:
eimsori [14]

answer is frequency

 

5 0
3 years ago
Read 2 more answers
A train is traveling away from you at 120 km/h. it blows its whistle, and you hear a tone of 0.400 kHz. Take the speed of sound
Vaselesa [24]

Answer:B)439.21 Hz

Explanation:

Given

velocity of train v=120 km/h\approx 120\times \frac{5}{18}=33.33 m/s

frequency of train f_a=0.400 kHz\approx 400 Hz

speed of sound c=340 m/s

frequency from Doppler effect can be calculated by

f_a=(\frac{c}{c+v})\cdot f

400=(\frac{340}{340+33.33})\cdot f

400=\frac{340}{373.33}\cdot f

f=400\times 1.098

f=439.21 Hz

5 0
3 years ago
A 0.12 g honeybee acquires a charge of +24pC while flying. The earth's electric field near the surface is typically 100 N/C, dow
shusha [124]

Answer:

150000000

\dfrac{F_e}{F_g}=0.00000203873598369

49050000 N/C

Explanation:

q = Charge = 24 pC

m = Mass of honeybee = 0.12 g

E = Electric field = 100 N/C

g = Acceleration due to gravity = 9.81 m/s²

1\ C=6.25\times 10^{18}\ electrons

Number electrons is

n=24\times 10^{-12}\times 6.25\times 10^{18}\\\Rightarrow n=150000000

The number of electrons added or removed was 150000000

Force is given by

F_e=Eq\\\Rightarrow F_e=100\times 24\times 10^{-12}\\\Rightarrow F_e=2.4\times 10^{-9}\ N

The ratio is

\dfrac{F_e}{F_g}=\dfrac{2.4\times 10^{-9}}{0.12\times 10^{-3}\times 9.81}\\\Rightarrow \dfrac{F_e}{F_g}=0.00000203873598369

The ratio is \dfrac{F_e}{F_g}=0.00000203873598369

Balancing the forces we get

Eq=mg\\\Rightarrow E=\dfrac{mg}{q}\\\Rightarrow E=\dfrac{0.12\times 10^{-3}\times 9.81}{24\times 10^{-12}}\\\Rightarrow E=49050000\ N/C

The electric field required is 49050000 N/C

4 0
4 years ago
Can someone help me with this. I'm not really sure if the right answer is c.
taurus [48]
It might be c I'm not sure either. Hope I helped
6 0
3 years ago
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