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skad [1K]
3 years ago
11

how many days does it take a team of drivers to drive a truck california and back to lansing if the drivers average 15m/s includ

ing breaks and traffic? california is 1800 miles from lansing
Physics
1 answer:
Scilla [17]3 years ago
4 0

Answer:

t = 2.2 [days] and is there is a round trip, it will be double time t = 4.4 [days]

Explanation:

First, we need to arrange the problem to work in the same unit system (SI).

We need to convert the 1800 [miles] to meters, therefore:

1800[miles] * \frac{1609.34[m]}{1[mile]} }=2896812[m] = 2896.8[km]

Now using the following equation of kinematics, for the avarage velocity  we have:

v=\frac{x}{t} \\where \\v=velocity [m/s]\\t = time [s]\\x=distance traveled [m]\\

therefore:

t=\frac{x}{v} \\t=\frac{2896812}{15}\\ t=193120.8[s]

Now we can convert from seconds into days.

193120.8[s]*\frac{1[hr]}{3600[s]}*\frac{1[day]}{24[hr]}\\  t = 2.2[days]

Now if the truck has the need to come back, the team will spend double time.

t= 4.4 [days]

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Which person would experience the greatest force of impact in a sudden collision? A 200 lb. man traveling 20 mph b 150 lb. woman
Alisiya [41]

Answer:

<em>The 150 lb woman at 30 mph would experience the greatest force of impact in a sudden collision.</em>

Explanation:

<u>Momentum </u>

The force of impact exerted on an moving object that suddenly stops or changes its movement is measures by the physics magnitude called Impulse, which can be computed with the formula

I=F.t

Where F is the force and t is the time that force acts to produce the impact on the object. The impulse is also defined as the change in the momentum of the object:

I=\Delta p=p_2-p_1

Or equivalently

I=m(v_2-v_1)

The question describes four situations where different persons and object suffer impact that make them stop from their moving state. Thus v_2=0 and the impulse is

I=-m.v_1

We are only interested in the relative magnitudes of each case, so we won't consider the sign in the calculations

Case 1: A 200 lb. man traveling 20 mph  

I_1=200(20)=4000\ lb.mph

Case 2: A 150 lb. woman at 30 mph

I_2=150(30)=4500\ lb.mph

Case 3: A 35 lb. infant at 75 mph

I_3=35(75)=2625\ lb.mph

Case 4: A 75 lb. child at 55 mph

I_4=75(55)=4125\ lb.mph

By comparing the results, we can see that the 150 lb woman at 30 mph would experience the greatest force of impact in a sudden collision.

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A is the square's area

s is the length of one of the square's sides

Let us take the derivative of both sides of the equation with respect to time t in order to determine a formula for finding the rate of change of the square's area over time:

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The chain rule says to take the derivative of s² with respect to s then multiply the result by ds/dt

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