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tatiyna
3 years ago
14

Will the velocity of the book change as it moves across thr surface with no friction

Physics
1 answer:
Bas_tet [7]3 years ago
7 0

Answer:

Friction always acts to oppose any relative motion between surfaces. ... If we push on the book with a force of less than 5 N, the book won't move, because the frictional force will exactly balance the force we apply. If we push with a 1 N force, a 1 N frictional force opposes us.

Explanation:

none

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If you punched thousands of holes in the aluminum foil of the scope (so there were more "holes" than "foil"), how many imageswou
klasskru [66]

Answer:

If you punched thousands of holes in the aluminum foil, you would see thousands of small images in the viewer.

Explanation:

If thousands of holes is punched/perforated in an aluminum foil, such that there were more holes than foil.

Thousands of small images would be formed, which can be seen in the viewer. Aluminum foil has a good reflective property which allows the thousands of holes punched to reflect equal number of images, although the images are smaller in size than the original image size.

3 0
3 years ago
A roundabout is a type of playground equipment involving a large flat metal disk that is able to spin about its center axis. A r
Zina [86]

Answer:

116.1 kgm²/s

1.12718 rad/s

Decreases

Explanation:

m = Mass of girl = 43 kg

M = Mass of roundabout = 120 kg

v = Velocity of roundabout = 2.7 m/s

r = Radius of roundabout = 1 m = R

I = Moment of inertia

Her angular momentum

L_i=mvr\\\Rightarrow L_i=43\times 2.7\times 1\\\Rightarrow L_i=116.1\ kgm^2/s

Magnitude of angular momentum is 116.1 kgm²/s

Here the angular momentum is conserved

L_f=L_i\\\Rightarrow I\omega=L_i\\\Rightarrow (\frac{1}{2}MR^2+mr^2)\omega=116.1\\\Rightarrow \omega=\frac{116.1}{\frac{1}{2}\times 120\times 1^2+43\times 1^2}\\\Rightarrow \omega=1.12718\ rad/s

Angular speed of the roundabout is 1.12718 rad/s

Initial kinetic energy

K_i=\frac{1}{2}mv^2\\\Rightarrow K_i=\frac{1}{2}43\times 2.7^2\\\Rightarrow K_i=156.735\ J

Final kinetic energy

K_f=\frac{1}{2}I\omega^2\\\Rightarrow K_f=\frac{1}{2}\times (\frac{1}{2}\times 120\times 1^2+43\times 1^2)\times 1.12718^2\\\Rightarrow K_f=65.43253\ J

The overall kinetic energy decreases as can be seen. This loss is converted to heat.

5 0
3 years ago
PLEASE HELP
Elan Coil [88]

Answer:

Explanation:

a_{x}=0 v_{xo}= v_{o}cos(delta)t a_{y}=-g v_{yo}=sinθ

X-direction                                     | Y-direction

x=x_o+v_{xo}t ⇒ x=v_{xo}cos(delta)t |

5 0
3 years ago
Speed is the ratio of the distance an object moves to (1 point)the amount of time needed to travel the distance.
Dennis_Churaev [7]

a) the distance an object moves to the amount of time needed to travel the distance.

i hope this helps :3

6 0
4 years ago
The 2nd largest hailstone every measured fell in Aurora, Nebraska, in 2003. The circumference of that hailstone was 16 inches. U
8_murik_8 [283]

Answer:

1. What was the diameter of the hailstone in inches_5.09_ and in cm___12.92___ and in feet ____0.42___?

2. What was the total volume of the hailstone in cubic inches___68.64___ and cubic feet____0.03____?

3. What was the fall velocity of this hailstone in m/s_____2.584____ and in mph___5.78_____?

Explanation:

1. If the circumference (L) of the stone is 16 inches, then from the following equation

L = 2\pi R

R = \frac{L}{2\pi} = \frac{16}{2\pi} = 2.54 ~inches

D = 2R = 5.09 ft

1 inch = 2.54 cm = 0.08 ft, so 5.09 inches = 12..92 cm = 0.42 ft

2. The total volume is

V = \frac{4}{3}\pi R^3 = \frac{4}{3}\pi (2.54)^3 = 68.64~in^3\\68.64 ~in^3 = 0.03~ft^3

3. The fall velocity is V = kd, where k = 20 if d is in cm. Let's calculate the fall velocity in cm.

V = 20*12.92 = 258.4~cm/s = 2.584~m/s

2.584 m/s = 5.78 mph

4 0
3 years ago
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