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sashaice [31]
3 years ago
10

A rocket engine applies a force of 50000 N for a distance of 20 m. how much work is done?​

Physics
1 answer:
zlopas [31]3 years ago
6 0

Answer:

1000000Nm

Explanation:

W=force*distance

   50000*20

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An object is in free fall. After 10 seconds calculate the distance fallen? *
Citrus2011 [14]

Answer:

9.81 × 10 = 98.1 meters

vertical displacement is s=1/2 at^2 + vt

initial vertical velocity is 0 so s=1/2 at^2

a in this instance is gravitational acceleration so 60m= 1/2 (9.81)t^2

solve for t, t = 3.497s. //I corrected this answer as just now I misread horizontal as vertical.

3 0
3 years ago
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Which is a example of speed? A)Cindy biked westward at 30km/h B)A Rock is the the left of a flowerpot C) A dog runs an average o
finlep [7]
I think the answer is A) Cindy biked westward at 30km/h. I'm sorry if I'm wrong. If that's not correct then it's definitely C) A dog runs an average of 8mp/h. I hope this helps. :) 
4 0
4 years ago
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For variables control, a circuit voltage will be measured using a sample of five circuits. The past average voltage for samples
astra-53 [7]

Answer:

Average :

UCL = 4.15

LCL = 2.65

Range :

UCL = 2.75

LCL = 0

Explanation:

Given :

Sample size, n = 5

Average, X = 3.4

Range, R = 1.3

A2 for n = 5 ; equals 0.577 ( X chart table)

For the average :

Upper Control Limit (UCL) :

X + A2*R

3.4 + 0.577(1.3) = 4.1501

Lower Control Limit (LCL) :

X - A2*R

3.4 - 0.577(1.3) = 2.6499

FOR the range :

Upper Control Limit (UCL) :

UCL = D4*R

D4 for n = 5 ; equals = 2.114

UCL = 2.114*1.3 = 2.7482

Lower Control Limit (LCL) :

LCL = D3*R

D3 for n = 5 ; equals = 0

LCL = 0 * 1.3 = 0

8 0
3 years ago
Tourists covered 255 km for a 4-hour ride by car and a 7-hour ride by train. what is the speed of the train, if it is 5 km/h gre
LekaFEV [45]
The distance covered by car is equal to (assuming it is moving by uniform motion) the product between the car's speed and the time of the car ride, 4 h:
S_c = v_c t_c
where
v_c is the car's speed
t_c = 4 h is the duration of the car ride

Similarly, the distance covered by train is equal to the product between the train's speed and the duration of the train ride, 7 h:
S_t = v_t t_t

The total distance covered is S=255 km, which is the sum of the distances covered by car and train:
S=255 km = S_c + S_t
which becomes
255 = 4 v_c + 7 v_t (1)
we also know that the train speed is 5 km/h greater than the car's speed:
v_t = 5 + v_c (2)

If we put (2) into (1), we find
255 = 4v_c + 7(5+v_c)
and if we solve it, we find
v_c = 20 km/h
v_t = 25 km/h

So, the car speed is 20 km/h and the train speed is 25 km/h.

4 0
3 years ago
A trolley is moving at constant speed in a friction compensated track. Some plasticine is dropped on the trolley and sticks on i
Maurinko [17]

Answer:

Since the momentum of the body remains constant ( conserved) the trolley slows down (its velocity reduces) since its mass increases.

5 0
2 years ago
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