Question

How many moles of nitrogen gas would be produced if 3.27 moles of copper(II) oxide were reacted with excess ammonia in the following chemical reaction? 2 NH3(g) + 3 CuO (s) – 3 Cu(s) + N2(g) + 3 H2O(g)​

Answer 1

Moles of Nitrogen(N₂) gas would be produced : 1.09

Further explanation

The reaction coefficient in a chemical equation shows the mole ratio of the components of the reactants and products

If one mole of the reactant or product is known, then we can determine the moles of the other compounds involved in the reaction

Reaction

2NH₃(g) + 3CuO (s) ⇒ 3Cu(s) + N₂(g) + 3 H₂O(g)​

Copper(II) oxide was reacted with excess Ammonia, so CuO as a limiting reactant and moles of the product is based on moles of CuO

moles of CuO = 3.27

From the equation, the mol ratio of CuO : mol N₂ = 3 : 1, so mol  N₂ :

$\tt \dfrac{1}{3}\times 3.27=1.09$