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The rate constant of the second order reaction is 0.137 M-1s-1.
<h3>What is the rate constant?</h3>
For the second order reaction we can write;
1/[A] = kt + 1/[A]o
[A]o = initial concentration
[A] = final concentration
k = rate constant
t = time
Now;
1/0.319 = 13.5k + 1/ 0.740
1/0.319 - 1/0.740 = 13.5k
3.13 - 1.35 = 13k
k = 3.13 - 1.35/13
k = 0.137 M-1s-1
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Answer:
For the first oxide, 1 g gives 0.888 g of copper.
Dividing by 0.888 tells us that 1.126 g gives 1 g of copper so has 0.126 g of oxygen.
For the second oxide, 1 g gives 0.798 g of copper.
Dividing by 0.798 tells us that 1.253 g gives 1 g of copper so has 0.253 g of oxygen.
So 1 g of copper combines with either 0.126 g or 0.253 g of oxygen.
Within the limits of experimental error, 0.253 is twice 0.126, confirming the law of multiple proportion.
Approximitly 0.013787375 moles
