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MariettaO [177]
2 years ago
7

What ocurrrs when the vapor pressure of a liquid is equal to the external atmospheric pressure

Chemistry
2 answers:
babymother [125]2 years ago
7 0

Answer:

The change from a liquid phase to a gaseous phase.

so the answer would be it changed to a gaseous phase

---------------

This is what occurs when the vapor pressure of the liquid is equal to the atmospheric pressure exerted on the liquid.

ElenaW [278]2 years ago
4 0
Changes to gaseous phase
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Which of the following is an element?
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Which statement explains why water is classified
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3 years ago
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Consider the following reaction 2 N2O(g) => 2 N2(g) + O2(g) rate = k[N2O]. For an initial concentration of N2O of 0.50 M, cal
den301095 [7]

Answer:

After 2.0 minutes the concentration of N2O is 0.3325 M

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Step 1: Data given

rate = k[N2O]

initial concentration of N2O of 0.50 M

k = 3.4 * 10^-3/s

Step 2: The balanced equation

2N2O(g) → 2 N2(g) + O2(g)  

Step 3: Calculate the concentration of N2O after 2.0 minutes

We use the rate law to derive a time dependent equation.

-d[N2O]/dt = k[N2O]

ln[N2O] = -kt + ln[N2O]i

 ⇒ with k = 3.4 *10^-3 /s

⇒ with t = 2.0 minutes = 120s

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ln[N2O] = -(3.4*10^-3/s)*(120s) + ln(0.5)

ln[N2O] = -1.101

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[N2O} = 0.3325 M

After 2.0 minutes the concentration of N2O is 0.3325 M

3 0
3 years ago
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