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Nina [5.8K]
3 years ago
13

For a given chemical reaction, the addition of a catalyst provides a different pathway that(1) decreases the reaction rate and h

as a higher activation energy
(2) decreases the reaction rate and has a lower activation energy
(3) increases the reaction rate and has a higher activation energy
(4) increases the reaction rate and has a lower activation energy
Chemistry
2 answers:
kykrilka [37]3 years ago
6 0
For a given chemical reaction, the addition of a catalyst provides a different pathway that "<span>(4) increases the reaction rate and has a lower activation energy"</span>
Komok [63]3 years ago
3 0

Answer: Option (4) is the correct answer.

Explanation:

Activation energy is the minimum amount of energy required by the reactants to participate in the chemical reaction.

Therefore, reactant molecules whose energy is less than the activation energy are not able to participate in the reaction. Hence, a catalyst lowers the activation energy so that molecules with less energy can also participate in the reaction.

Thus, a catalyst is a specie that increases the reaction rate and has a lower activation energy.

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Determine the number of:
Elena-2011 [213]

Answer: Ag:  2.79x10^22 atoms

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Explanation:

5.0 grams of Ag is 0.0464 moles of Ag.  (0.0464 moles)*(6.02x10^23 atoms/mole) = 2.79x10^22 atoms Ag

(0.50 moles)*(6.02x10^23 molecules/mole)*(2 C atoms/molecule) = 6.02x10^23 atoms of C

3 0
2 years ago
Use the chemical equation and the bond diagram to answer the question.
Scilla [17]

Answer:

O=O bond

Explanation:-

Note it down that the bond having highest Hydrogen enthalpy has strongest bond.

Now

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  • H-H(432KJ/mol)

Hence

\\ \bull\sf\dashrightarrow O=O>O-H>H-H>O-O

5 0
2 years ago
Calculate the pH of the resulting solution if 26.0 mL of 0.260 M HCl(aq) is added to:
enyata [817]
So in your question that ask to calculate the Ph result of the resulting solution if 26 ml of 0.260 M HCI(aq) is added to the following substance. The the result are the following:
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7 0
3 years ago
Be sure to answer all parts. A concentration cell consists of two Sn/Sn2+ half-cells. The electrolyte in compartment A is 0.23 M
kolbaska11 [484]

Answer:

Part A. The half-cell B is the cathode and the half-cell A is the anode

Part B. 0.017V

Explanation:

Part A

The electrons must go from the anode to the cathode. At the anode oxidation takes place, and at the cathode a reduction, so the flow of electrons must go from the less concentrated solution to the most one (at oxidation the concentration intends to increase, and at the reduction, the concentration intends to decrease).

So, the half-cell B is the cathode and the half-cell A is the anode.

Part B

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E°cell = E° - (0.0592/n)*log[anode]/[cathode]

Where n is the number of electrons being changed in the reaction, in this case, n = 2 (Sn goes from S⁺²). Because the half-reactions are the same, the reduction potential of the anode is equal to the cathode, and E° = 0 V.

E°cell = 0 - (0.0592/2)*log(0.23/0.87)

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3 0
3 years ago
Which is a chemical property of oxygen?
Troyanec [42]

Answer: I think the answer is 1

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Explanation:

5 0
3 years ago
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