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Inga [223]
3 years ago
15

A spin balancer rotates the wheel of a car at 480 revolutions per minute. if the diameter of the wheel is 26 inches, what road s

peed is being tested? express your answer in miles per hour. at how many revolutions per minute should the balancer be set to test a road speed of 80 miles per hour?
Physics
1 answer:
Mariana [72]3 years ago
3 0
Part A:
To answer this item, we need to convert the given revolutions per minute in speed expressed as miles per hour. In order to do so, we need to use the dimensional analysis and the appropriate conversion factor.
 
We calculate the circumference that is covered by the wheel.
     C = πD
where C is the circumference and D is the diameter.

Substitute the known values,
       C = π(26 in) = 81.68 inches

The speed tested is calculated below.
      s = (81.68 inches/rev)(480 rev/min)(1 mil/63360 inches)(60 min/1 hr)
            s = 37.127 mil/h

<em>ANSWER: 37.127 mil/h</em>

Part B:
Similar to what was done in Part A, the setting of the balancer is calculated below,
       setting = (80 mil/h)(1h/60 min)(63360 in/1 mil)(1 rev/81.68 in)
         setting = 1034.23 rev/min

<em>ANSWER: 1034.23 rev/min</em>
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A rectangular reflecting pool is 56.5 ft wide and 141 ft long. What is the area of the pool in square meters
konstantin123 [22]

By definition, the area of the pool is 740.112 m².

<h3>Definition of area</h3>

The area is the measure of a space delimited by a contour which is called perimeter.

That is, the area gives an idea of ​​how much surface a figure covers and is defined as the measure of the region or surface enclosed by a geometric figure.

<h3>Area of a rectangle</h3>

A rectangle is a flat geometric figure with four sides, of which two sides that are opposite parallel to each other have the same length and the remaining two have another length.

The area of ​​a rectangle is calculated by multiplying the lengths of two contiguous sides of the figure which are different from each other, that is, the length is multiplied by the width:

Area= length× width

<h3>This case</h3>

A rectangular reflecting pool is 56.5 ft wide and 141 ft long. So, the area of the rectangular pool is calculated as:

Area= length× width

Area= 141 ft× 56.5 ft

Solving:

<u><em>Area= 7966.5 ft²= 740.112 m²</em></u> (being 1 ft²= 0.092903 m²)

So, the area of the pool is 740.112 m².

Learn more about the area of a rectangle:

brainly.com/question/11202023

brainly.com/question/13048427

4 0
3 years ago
A ball of mass 0.250 kg and a velocity of + 5.00 m/s collides head-on with a ball of mass 0.800 kg that is initially at rest. No
Mademuasel [1]

Answer:

v_1=-2.616\ m/s

Explanation:

Given that,

Mass of ball 1, m_1=0.25\ kg

Initial speed of ball 1, u_1=5\ m/s

Mass of ball 2, m_2=0.8\ kg

Initial speed of ball 2, u_2=0 (at rest)

After the collision,

Final speed of ball 2, v_2=2.38\ m/s

Let v_2 is the final speed of ball 1.

Initial momentum of the system is :

p_i=m_1u_1+m_2u_2

p_i=0.25\times 5+0

p_i=1.25\ m/s

Final momentum of the system is :

p_f=m_1v_1+m_2v_2

p_f=0.25\times v_1+0.8\times 2.38

p_f=0.25 v_1+1.904

According the law of conservation of linear momentum :

initial momentum = final momentum

1.25=0.25 v_1+1.904

v_1=-2.616\ m/s

So, the final velocity of ball 1 is (-2.616)m/s.

8 0
3 years ago
I really need your help I will mark you brainliest!
Artist 52 [7]
Https://www.lsop.colostate.edu/wp-content/uploads/sites/6/2014/10/HurricanesGoCounterclockwise.pdf
4 0
3 years ago
Calcular la aceleración que produce una fuerza de 40 N sobre un cuerpo con 88 Kg de masa. Expresar el resultado en m⁄s^2 *
tigry1 [53]

Answer:

a = 0.45 m/s²

Explanation:

The given question is ''Calculate the acceleration that produces a force of 40 N on a body with 88 kg of mass".

Given that,

Force, F = 40 N

Mass of the body, m = 88 kg

The net force acting on the body is given by :

F = ma

Where

a is the acceleration of the body

a=\dfrac{F}{m}\\\\a=\dfrac{40\ N}{88\ kg}\\\\a=0.45\ m/s^2

So, the required acceleration is 0.45 m/s².

4 0
3 years ago
Gravity always tries to collapse the mass of a star toward its center. What mechanism can oppose this gravitational collapse for
Tamiku [17]

Answer:

The gravity collapsing the core, increases pressure causing the fusion of hydrogen to helium. The newly formed helium creates outward pressure. The pressure balances the gravitational inward pull. This is the hydrostatic equilibrium and it occurs throughout the main sequence phase.

6 0
4 years ago
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