Ask question

Ask question

All categories

3 years ago

11

a car accelerates at a constant rate from 15 m/s to 25 m/s while it travels a distance of 125 m. How long does it take to achiev

e this speed?

1 answer:

atroni [7]3 years ago

6 0

T=Vf-Vi/s
25m/s -15m/s/ 125m
10m/s /125m
=0.08s
I hope it’s correct !

You might be interested in

A 1.2 kg block is held at rest against the spring with a force constant k= 730 N/m. Initially, the spring is compressed a distan

mariarad [96]

Answer:

d = 9.69 cm

Explanation:

given,

mass of the block = 1.2 Kg

spring force constant(k) = 730 N/m

spring is compressed = d = ?

rough patch width = 5 cm

μ_k = 0.44

work done by friction = energy lost

$\mu_k mg \times x = \dfrac{1}{2}kd^2-\dfrac{1}{2}mv^2$

$0.44\times 1.2 \times 9.8 \times 0.05 = \dfrac{1}{2}\times 730 \times d^2-\dfrac{1}{2}\times 1.2 \times 2.3^2$

$3.432 = 365 d^2$

$d = \dfrac{3.432}{365}$

d = 0.0969 m

d = 9.69 cm

5 0

3 years ago

Match each type of wave to the way it moves.

oee [108]

Answer:

Transverse wave- Back and forth at right angles to the direction of the wave arrow.

longitudinal wave- bask and forth in the direction of the motion of the motion of the wave.

electromagnetic wave- two alternating waves moving at right angles to each other.

Explanation:

In a longitudinal wave, the particles vibrate at right angles in reference to the wave motion.

In a transverse wave, the particles vibrate parallel to the wave motion

Electromagnetic waves occur as a result of the interaction between two waves and are normally transverse in nature.

3 0

3 years ago

HELP PLS RIGHT ANSWER GETS BRAINLIEST!!!!

mr Goodwill [35]

Answer:

<em><u>♧</u></em><em><u> </u></em><em><u>Write</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>correct</u></em><em><u> </u></em><em><u>abbreviation</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>each</u></em><em><u> </u></em><em><u>metric</u></em><em><u> </u></em><em><u>unit</u></em><em><u>.</u></em>

kg
m
g
mL
mm
L
km
cm
mg

<em><u>♧</u></em><em><u> </u></em><em><u>Try</u></em><em><u> </u></em><em><u>these</u></em><em><u> </u></em><em><u>conversions</u></em><em><u>,</u></em><em><u> </u></em><em><u>using</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>ladder</u></em><em><u> </u></em><em><u>method</u></em><em><u>.</u></em>

2 g
104000 m
4.8 m
5600 g
0.8 cm
5000 mL
0.198 kg
0.075 L
0.5 m
560 cm
160 mm
2.5 km
65000 mg
63 mm
0.12 g

<em><u>♧</u></em><em><u> </u></em><em><u>Compare</u></em><em><u> </u></em><em><u>using</u></em><em><u> </u></em><em><u><</u></em><em><u>,</u></em><em><u> </u></em><em><u>></u></em><em><u>,</u></em><em><u> </u></em><em><u>or</u></em><em><u> </u></em><em><u>=</u></em><em><u>.</u></em>

16. <

17. >

18. =

19. =

20. <

21. >

8 0

3 years ago

How is Newton’s third law of motion involved when you jump straight upward?

Bad White [126]

<span>Newtons 3rd law of motion states that action and reaction are equal and opposite. How it applies in this statement is that when you jump straight upward you hit the floor and you experience an equal magnitude of force against your feet, because force always acts as a result of two objects and whenever forces occur they do so in pairs of equal magnitude acting in opposite directions. I hope this helps!</span><span>
</span>

3 0

3 years ago

Read 2 more answers

Can uh help in in this question step by step

Luda [366]

Initial velocity=u=72km/h

Convert to m/s

$\\ \sf \longmapsto 72\times \dfrac{5}{18}=5(4)=20m/s$

Final velocity=v=0m/s
Time=2s=t

$\\ \sf \longmapsto Acceleration=\dfrac{v-u}{t}$

$\\ \sf \longmapsto Acceleration=\dfrac{0-20}{2}$

$\\ \sf \longmapsto Acceleration=\dfrac{-20}{2}$

$\\ \sf \longmapsto Acceleration=a=-10m/s^2$

Distance be s

Using second equation of kinematics

$\\ \sf \longmapsto s=ut+\dfrac{1}{2}at^2$

$\\ \sf \longmapsto s=20(2)+\dfrac{1}{2}(-10)(2)^2$

$\\ \sf \longmapsto s=40+(-20)$

$\\ \sf \longmapsto s=40-20$

$\\ \sf \longmapsto s=20m$

Now

Mass=m=5000kg

Using newtons second law

$\\ \sf \longmapsto Force=ma$

$\\ \sf \longmapsto Force=5000(-10)$

$\\ \sf \longmapsto Force=-50000N$

Force is in opposite direction so its negative

$\\ \sf \longmapsto Force=50kN$

7 0

3 years ago

Read 2 more answers