Answer:
a)0.024
b)0.148
Explanation:
Let 's represent the set of deer ticks Carrying Lyme disease with L and the set of deer ticks carrying Human Granulocytic Ehrlichiosis with H
Given:
P(L) = 0.16
P(H) = 0.10
P(L n H) = 0.1 ·P( L u H )
Hence, P( L u H) = 10 ·P( L nH)
(a)
Hence. using the equation. P(L U H) = P(L) + P(H) - P(L n H)
Hence, 10 · P(L n H ) = 0.16 + 0.1 - P(L n H )
Hence, 11 · P(L n H) = 0.16 + 0.1 = 0.26
Hence, P(L n H) =
0.26/11=0.024
(b)
We know that condition probability P(H ║ L) = p(L n H)/P(L)
hence, P(H ║ L) =(0.26/11)/0.16 =0.148
Answer:
A. True
Explanation:
This is because these aircraft experiences different types of vibrations which include buffet vibrations and aerodynamic flutter. Buffet vibrations are vibrations caused by an interruption of airflow. Buffet vibrations are usually felt when the aerodynamic brakes are applied.
Aeroelastic flutter is the most dangerous type of vibration. This occurs when energy added to the wings due to airflow is greater than that lost due to damping. Aeroelastic flutter can cause aircraft to fail when the vibrations are large enough.
Explanation:
Below is an attachment containing the solution.
Answer:
(D) parasite........................
