Answer:
48.16 %
Explanation:
coefficient of restitution = 0.72
let the incoming speed be = u
let the outgoing speed be = v
kinetic energy = 0.5 x mass x 
- incoming kinetic energy = 0.5 x m x
- coefficient of restitution =

0.72 =
v = 0.72u
therefore the outgoing kinetic energy = 0.5 x m x 
outgoing kinetic energy = 0.5 x m x 
outgoing kinetic energy = 0.5184 (0.5 x m x
)
recall that 0.5 x m x
is our incoming kinetic energy, therefore
outgoing kinetic energy = 0.5184 x (incoming kinetic energy)
from the above we can see that the outgoing kinetic energy is 51.84 % of the incoming kinetic energy.
The energy lost would be 100 - 51.84 = 48.16 %
Answer:


Explanation:
1 full revolution is
let \theta be the angle of Ron's position.
At t = 0. 
one full revolution occurs in 12 sec, so his angle at t time is

r is radius of circle and it is given as


for r = 30 sec


however, that is centered at (0,0) and the positioned at time t = 0 is (30,0). it is need to shift so that the start position is (30,45). it can be done by adding to y


Answer:
The force exerted by the rope on her arms is 273.7 N = 0.274 kN
Explanation:
Step 1: Data given
Mass of the ice skater = 55.6 kg
Velocity = 1.73 m/s
She then moves in a circle of radius 0.608 m around the pole.
Step 2:
Force exterted by the horizontal rope is the centripetal force acting on theice skater:
Fc = M*ac
⇒ with ac = v²/r
Fc = M * v²/r
Fc = 55.6 * 1.73²/0.608
Fc =273.69 N
The force exerted by the rope on her arms is 273.7 N = 0.274 kN