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Arlecino [84]
3 years ago
9

Dewey's soccer team purchased uniforms and equipments for a total cost of $912 . The equipment cost $ 612 , and the uniforms cos

t $ 25 per player. how many uniforms did the school purchase

Mathematics
2 answers:
love history [14]3 years ago
8 0

Answer:

12 uniforms

Step-by-step explanation:

first you subtract 612 from 912 and get 300

then you divide 300 by the cost of uniforms (25)

then you get an answer of 12

Andru [333]3 years ago
8 0

Answer:

300

Step-by-step explanation:


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Dima020 [189]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56  

And rounded up we have that n=2663

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

t_{\alpha/2}=-2.58, t_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.025 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We can assume an estimated proportion of \hat p =0.5 since we don't have prior info provided. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.025}{2.58})^2}=2662.56  

And rounded up we have that n=2663

6 0
4 years ago
Eight students ran a 180-meter course during their physical education class. The chart shows the time it took each student to co
lakkis [162]

Answer:

Step-by-step explanation:

Speed of student 1 = 180/30= 6 m/sec

speed of student 2= 180/32= 5.62 m/sec

speed of student 3= 180/33= 5.45 m/sec

speed of student 4= 180/35= 5.14 m/sec

speed of student 5= 180/37= 4.86 m/sec

speed of student 6= 180/38= 4.73 m/sec

speed of student 7= 180/40= 4.5 m/sec

speed of student 8= 180/32= 4 m/sec

average speed is = (6+5.62+5.45+5.14+4.86+4.73+4.5+4)/8

hence, average speed is= 5.04

hence, the average speed of student 1 = 6m/sec

how much faster is average speed of student 1 than average speed= 6- 5.04 = 0.96

hence, average speed of student 1 is 0.96 m/sec more thanthe average speed.

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3 years ago
on a time Find the midpoint of segment GL if G (- 2, 46) and L (4, 10). Write your anwer in coordinate pair form (x, y)
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Step-by-step explanation:

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g100num [7]

Answer:

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Step-by-step explanation:

A cross-sectional study is a type of study that involves the data i.e. taken from a population for a specific time period.

Here study shows the peoples interest in variables that are be chosen

In the given situation, since a town obtains a data of the current employment for 10,000 of its total citizens

So this represents the cross-sectional

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4 years ago
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Answer:

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Step-by-step explanation:

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