Answer:the
8/9 h
Explanation:
Height = 1/2 a T^2 now change to T/3
now height = 1/2 a (T/3)^2 =<u> 1/9</u> 1/2 a T^2 <===== it is 1/9 of the way down or 8/9 h
Mass of car, m = 4060 kg
Spring constant, k = 8.00 x 10⁶ N/m
Spring compression, x = 3.72 cm = 3.72 x 10⁻² m
Let the car strike the wall with speed v m/s.
The kinetic energy of the car is released into the stored energy of the spring (if losses are ignored), so that
(1/2)mv² = (1/2)kx²
(4060 kg)*(v m/s)² = (8 x 10⁶ N/m)(3.72 x 10⁻² m)²
4060 v² = 1.1701 x 10⁴
v = 1.6513 m/s
Answer: 1.65 m/s (nearest hundredth)
I'm not too sure about this one, I've been having second guesses on it myself. But, what I put is A. Velocity. That could be wrong though, so don't take my word for it! ;)
Answer:
1
Explanation:
The car's acceleration must be equals to or less than the car's velocity, cause of the change in velocity.
