_dThe radius of curvature of a subatomic particle under a magnetic field is given by the following formula:

Where:

We can determine the quotient between the velocity and the charge of the deuteron particle from the formula. First, we divide both sides by the mass:

Now, we multiply both sides by the magnetic field "B":

Since the charge of the deuterion is the same as the charge of the proton and the velocity we are considering are the same this means that the quotient between velocity and charge is the same for both particles. Therefore, we can apply the formula for the radius again, this time for the proton:

And substitute the quotient between velocity and charge:

Now, we cancel out the magnetic field:

Now, we substitute the values:

Solving the operations:

Therefore, the radius is 19.3 cm.
Answer:
3.97 m/s
Explanation:
Speed is defined as the distance covered per unit time. Therefore, s=d÷t=d/t
Where d is distance and t is time
Given distance of 5 km and time of 21 minutes the speed would be given by dividing 5 km by 21 min. However, speed is expressed as km/h or m/s or miles per hour etc. So we nees to get our speed in one of these standard units.
Going for m/s
Conversion
1 km has 1000m hence
5 km=5*1000=5000m
1 min has 60 seconds hence
21 min=21*60=1260 s
Speed=5000m÷1260s=3.9682539682538 m/s
Rounded off, s=3.97 m/s
It passes through C the Electron Cloud