-Positively charged nucleus
-Empty spaced
-Dense core
Answer:
the surface is tilted or uneven...
The pressure at the depth h in the ocean is given by (Stevin's law)
![p= p_0 + \rho g h](https://tex.z-dn.net/?f=p%3D%20p_0%20%2B%20%5Crho%20g%20h)
where
![p_0 = 1.0 \cdot 10^5 Pa](https://tex.z-dn.net/?f=p_0%20%3D%201.0%20%5Ccdot%2010%5E5%20Pa)
is the atmospheric pressure
and
![\rho g h](https://tex.z-dn.net/?f=%5Crho%20g%20h)
is the pressure exerted by the column of water of height h=4267 m, with
![\rho = 1000 kg/m^3](https://tex.z-dn.net/?f=%5Crho%20%3D%201000%20kg%2Fm%5E3)
being the water density and
![g=9.81 m/s^2](https://tex.z-dn.net/?f=g%3D9.81%20m%2Fs%5E2)
.
Substituting, we find
![p=1.0 \cdot 10^5 Pa + (1000 kg/m^3)(9.81 m/s^2)(4267 m)=4.20 \cdot 10^7 Pa](https://tex.z-dn.net/?f=p%3D1.0%20%5Ccdot%2010%5E5%20Pa%20%2B%20%281000%20kg%2Fm%5E3%29%289.81%20m%2Fs%5E2%29%284267%20m%29%3D4.20%20%5Ccdot%2010%5E7%20Pa)
We want to convert this into atmospheres: we know that 1 atm corresponds to the atmospheric pressure at sea level, so
![1 atm=1.0\cdot 10^5 Pa](https://tex.z-dn.net/?f=1%20atm%3D1.0%5Ccdot%2010%5E5%20Pa)
, therefore we just need to divide by this number:
Answer:
x=16.10°
Explanation:
You can go through a bunch of equations, but basically the cabinet can be moved until the CG is past the vertical line of the rotation point. After the CG crosses the line the weight of the cabinet will keep the rotation going in the direction.
to Find the angle from one corner to the CG
angle =atan(52/15) = 73.90
So, to make that angle vertical...
90° = x + 73.90°
x=16.10°
The answer you are looking for is either
A)<span>The ball that went out of the park shows more work because the force applied was greater or
</span><span>C)The ball that went out of the park shows more work because the distance was greater</span>