a man stands on a flat surface and shoots an arrow vertically into the sky at avelocity of 60 meters per second. calculate the m
aximum height the arrow reached. what was the velocity of the car when it hit the ground?
1 answer:
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Answer:
8977.7 kg/m^3
Explanation:
Volume of water displaced = 55 cm^3 = 55 x 10^-6 m^3
Reading of balance when block is immersed in water = 4.3 N
According to the Archimedes principle, when a body is immersed n a liquid partly or wholly, then there is a loss in the weight of body which is called upthrust or buoyant force. this buoyant force is equal to the weight of liquid displaced by the body.
Buoyant force = weight of the water displaced by the block
Buoyant force = Volume of water displaced x density of water x g
= 55 x 10^-6 x 1000 x .8 = 0.539 N
True weight of the body = Weight of body in water + buoyant force
m g = 4.3 + 0.539 = 4.839
m = 0.4937 kg
Density of block = mass of block / volume of block
=
Density of block = 8977.7 kg/m^3
Answer:
Potential energy is
Explanation:
The potential energy depends on the mass, the acceleration of gravity g and the height at which the object or person is.
Potential energy
In this case we would need to know the exact mass of the hiker in order to calculate the potential energy.
But we know the values of g and h
So, the potential energy
m is the mass of the hiker, wich is not in the description of the problem.