Gain in decibels is given by;
Gain db = 10*log (Po/Pi), where Po = Power output, Pin = Power input
Substituting;
Gain in db = 10 * log (50/5) = 10 db
The total gauge pressure at the bottom of the cylinder would
simply be the sum of the pressure exerted by water and pressure exerted by the
oil.
The formula for calculating pressure in a column is:
P = ρ g h
Where,
P = gauge pressure
ρ = density of the liquid
g = gravitational acceleration
h = height of liquid
Adding the two pressures will give the total:
P total = (ρ g h)_water + (ρ g h)_oil
P total = (1000 kg / m^3) (9.8 m / s^2) (0.30 m) + (900 kg /
m^3) (9.8 m / s^2) (0.4 - 0.30 m)
P total = 2940 Pa + 882 Pa
P total = 3,822 Pa
Answer:
The total gauge
pressure at the bottom is 3,822 Pa.
1/2*2.8*x^{2}=2.8*9.81*1.50
X=5.425
Because K.E=1/2*M*V² and it is equal to P.E in the conservation of energy which means its K.E=P.E
P.E=m*g*h
So K.E equals 1/2*2.8*(5.425)²=41.20
Using the cosine rule (a^2 = b^2 + c^2 - 2bc cos A), we can work out the displacement:
Displacement = a
b = 30
c = 50
A = 180 - 35 = 145 degrees.
a^2= 900 + 2500 -1500*-0.81915...
= 3400 + 1228.728...
= 4628.72...
a = 68.034...
= 68.0m (to 3s.f.).
To work out the angle from starting place, use another configuration of the cosine rule:

:
cos (C)=

= 3028.7.../4080
= 0.7423...
C = 42.069... degrees
= 042 bearing
Answer:
The efificiency is 0,25 of the machine (25%). See the explanation below
Explanation:
We calculate the efficiency with this formula:
Efficiency = energy obtained/energy supplied= 300 Joule/1200 Joule
Efficiency= 0,25
Efficiency(%) = 0,25 x100 = 25%