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4 years ago

How long does it take venus to orbit the sun

2 answers:

6 0

Venus is about 67 million miles away from the sun. It is hot there. Venus is almost the same size as planet Earth. One year on Venus is about 225 Earth days. A day on Venus is about 243 Earth days long because Venus rotates very slowly. On Venus a day is longer than a year and a year shorter than a day.

It take Venus 225 days to orbit the sun.

kodGreya [7K]4 years ago

5 0

The answer is 225 days

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Ethan made a diagram to compare examples of the first and second laws of thermodynamics. What belongs in the areas marked X and

Thepotemich [5.8K]

First law of thermodynamics:

It states that "Energy neither be created nor it can be destroyed". simply it converts one form of energy into another form.

It is also known as "law of conservation of energy"

Limitations of First law

It doesn't provide a clear idea about the direction of transfer of heat.
It doesn't provide the information that how much heat energy converted inti work.
Its not given any practical applications.

II law of thermodynamics:

It states that "the total entropy of the system can never decrease over time"

It is strongly proved by two laws, they are

1. Kelvin-plank statement:

He stated that "any engine does not give 100% efficiency". It violates the Perpetual motion of machine II kind(PMM-II).

2. Classius statement: 

  It states that "Heat always flows from high temperature body to low temperature body, without aid of external energy".

Also it stated that " Heat can also be transferred from low temperature body to high temperature body, by the aid of an external energy".

Applications of II law: 

Refrigeration &Air conditioning, Heat transfer, I.C. engines, etc.

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3 years ago

Read 2 more answers

Objects falling through the air experience a type of friction called air resistance

polet [3.4K]

True is the answer ndndndjjdjd

8 0

3 years ago

Read 2 more answers

Another word for transformations in science

Gnesinka [82]

Change, Alteration, Variation, Remaking etc...

7 0

3 years ago

lasers 1 and 2 emit light of the same color, and the electric field in the beam of laser 1 is twice as strong as the e-field of

bonufazy [111]

Answer:

The intensity of laser 2 is 4 times of the intensity of laser 1.

Explanation:

The intensity in terms of electric field is given by :

$U=\dfrac{1}{2}\epsilon_o E^2$

E is electric field

It means, $U\propto E^2$

In this problem, lasers 1 and 2 emit light of the same color, and the electric field in the beam of laser 1 is twice as strong as the e-field of laser 2.

Let E is electric field in the beam of laser 1 and E' is the electric field in the beam of laser 2. So,

$\dfrac{U}{U'}=(\dfrac{E}{E'})^2$

We have,

E'=2E

So,

$\dfrac{U}{U'}=\dfrac{E^2}{(2E)^2}\\\\\dfrac{U}{U'}=\dfrac{E^2}{4E^2}\\\\\dfrac{U}{U'}=\dfrac{1}{4}\\\\U'=4\times U$

So, the intensity of laser 2 is 4 times of the intensity of laser 1.

6 0

3 years ago

Estimate the number of photons emitted per second from 1.0 cm2 of a person's skin if a typical emitted photon has a wavelength o

Diano4ka-milaya [45]

Answer:

2.63 x 10^18

Explanation:

A = 1 cm^2 = 1 x 10^-4 m^2

λ = 10,000 nm = 10,000 x 10^-9 m = 10^-5 m

T = 37 degree C = 37 + 273 = 310 k

Energy of each photon = h c / λ

where, h is the Plank's constant and c be the velocity of light

Energy of each photon = (6.63 x 10^-34 x 3 x 10^8) / 10^-5 = 1.989 x 10^-20 J

Energy radiated per unit time = σ A T^4

Where, σ is Stefan's constant

Energy radiated per unit time = 5.67 x 10^-8 x 10^-4 x 310^4 = 0.05236 J

Number of photons per second = Energy radiated per unit time / Energy of

each photon

Number of photons per second = 0.05236 / (1.989 x 10^-20) = 2.63 x 10^18

4 0

3 years ago