Answer:
T=26.03 N
Explanation:
Given that
Distance between poles = 12 m
Mass of block m= 4 kg
Sag distance = 5 m
Lets take tension in the clothesline is T.
The component of tension in vertical direction will be T cosθ.
By force balancing
2 T cosθ = 40
here
θ=39.80°
2 T cos39.8 = 40
T=26.03 N
As we know that electrostatic force between two charges is given as
here we know that electrostatic repulsion force is balanced by the gravitational force between them
so here force of attraction due to gravitation is given as
here we can assume that both will have equal charge of magnitude "q"
now we have
now we have
Answer:
The amount of kinetic energy lost during the collision is 60.75 J
Explanation:
The given parameters are;
The mass of the object moving in the +x direction, m₁ = 1.00 kg
The velocity of the object moving in the +x direction, v₁ = 10.0 m/s
The mass of the object moving in the -x direction, m₂ = 1.50 kg
The velocity of the object moving in the +x direction, v₂ = 5.00 m/s
The final velocity of the 1.00 kg mass after collision, v₃ = 4.00 m/s
The direction of motion of the 1.00 kg mass after collision = -x direction
The total initial kinetic energy of the system, = 1/2·m₁·v₁² + 1/2·m₂·v₂²
∴ = 1/2×1.00×10² + 1/2×1.50×5² = 68.75 J
The final kinetic energy of the system, = 1/2·m₁·v₃²
= 1/2×1.00×4² = 8 J
The amount of kinetic energy lost during the collision, is given as follows;
=
-
= 8 J - 68.75 J = -60.75 J
The amount of kinetic energy lost during the collision = 60.75 J.