Answer:
0.246 kg
Explanation:
There is some info missing. I think this is the original question.
<em>A chemist adds 370.0mL of a 2.25 M iron(III) bromide (FeBr₃) solution to a reaction flask. Calculate the mass in kilograms of iron(III) bromide the chemist has added to the flask. Be sure your answer has the correct number of significant digits.</em>
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We have 370.0 mL of 2.25 M iron(III) bromide (FeBr₃) solution. The moles of FeBr₃ are:
0.3700 L × 2.25 mol/L = 0.833 mol
The molar mass of iron(III) bromide is 295.56 g/mol. The mass corresponding to 0.833 moles is:
0.833 mol × 295.56 g/mol = 246 g
1 kilogram is equal to 1000 grams. Then,
246 g × (1 kg/1000 g) = 0.246 kg
<u>Answer:</u> The half life of the given radioactive isotope is 43.86 minutes
<u>Explanation:</u>
Rate law expression for first order kinetics is given by the equation:
![k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
where,
k = rate constant = ?
t = time taken for decay process = 233 minutes
= initial amount of the reactant = 0.500 M
[A] = amount left after decay process = 0.0125 M
Putting values in above equation, we get:

The equation used to calculate half life for first order kinetics:

where,
= half-life of the reaction = ?
k = rate constant = 
Putting values in above equation, we get:

Hence, the half life of the given radioactive isotope is 43.86 minutes
Answer: -
Rimmed steel does not contain nickel.
Explanation: -
Rimmed steel is a deoxidised low carbon steel. Deoxidation leads to formation of rims in the iron.
Carbon, sulfur and phosphorus is present in rimmed steel. The concentrations of these vary from the outer rim to the inner rim. It is not as tough as other steel.
Hence it is primarily used for products where a lot of bending is required. Thus Rimmed steel does not contain nickel.