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Xelga [282]
3 years ago
12

A motorcycle moving initially at a velocity of 20 m/s accelerates

Chemistry
1 answer:
valina [46]3 years ago
4 0

Answer:

40m/s

Explanation:

final velocity is = initial velocity + Acceleration x time

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GIVING BRAINLIEST
Salsk061 [2.6K]

Answer:

D) Cool air is warming quickly.

Explanation:

d is the answer.

5 0
3 years ago
Read 2 more answers
How many unpaired electrons are there in <br> Cu1+ ion
goldfiish [28.3K]
If electrons are negative, losing an electron makes the ion positive.
Therefore Cu1+ contains 1 unpaired electron.
8 0
4 years ago
suppose you want to treat if a sample compound is ionic. you have these materials: the solid compound, a glass container, a spoo
xz_007 [3.2K]
An ionic compound is a substance that contains atoms that are bonded together through an ionic bond, where electrons are transferred from one atom to another. For the given experiment above, the material that is missing from the list is WATER or solvent. It is necessary because conduction through water will help you identify if a sample compound is ionic through its electrolytes. <span>Ionic compounds that are soluble are typically electrolytes</span>
6 0
3 years ago
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If the total pressure of water vapor and hydrogen gas is 1.02 atm and the partial pressure of the water at 22.0 C is 0.13 atm, w
ira [324]

Answer:

0.89 atm  is the pressure of the hydrogen gas

Explanation:

We can use the molar fractions to solve this

Sum of molar fractions (hydrogen + water vapor) = 1

Molar fraction = Pressure gas / Total pressure

Molar fraction water vapor = 0.13 atm/1.02 atm = 0.127

1 - 0.127 = 0.873 (Molar fraction H2)

0.873 = Pressure H2 / Total pressure

0.873 = Pressure H2 / 1.02 atm

0.873 . 1.02atm = 0.89 atm

8 0
4 years ago
4 moles of monoatomic ideal gas is compressed adiabatically causing the temperature to increase from 300 K to 400 K. Calculate t
yawa3891 [41]

Answer:

the work done on the gas is 4,988.7 J.

Explanation:

Given;

number of moles of the monoatomic gas, n = 4 moles

initial temperature of the gas, T₁ = 300 K

final temperature of the gas, T₂ = 400 K

The work done on the gas is calculated as;

W = \Delta U = nC_v(T_2 -T_1)

For monoatomic ideal gas: C_v = \frac{3}{2} R

W = \frac{3}{2} R \times n(T_2-T_1)

Where;

R is ideal gas constant = 8.3145 J/K.mol

W = \frac{3}{2} R \times n(T_2-T_1) \\\\W = \frac{3}{2} (8.3145) \times 4(400-300) \\\\W =  \frac{3}{2} (8.3145) \times 4(100)\\\\W = 4,988.7 \ J

Therefore, the work done on the gas is 4,988.7 J.

4 0
3 years ago
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