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Mkey [24]
3 years ago
10

The following ionization energies were found for an unknown element: -

Chemistry
1 answer:
Alika [10]3 years ago
7 0

Answer:

The common ion will be di-positive ion.

Explanation:

The ionization energy is defined as the amount of energy needed for removal of most loosely bound electron from an isolated atom in gaseous state.

The low ionization energy shows that the atom is able to give electron easily as after losing electron it may attain noble gas configuration or half filled stability.

Here the first and second ionization energy, both are low suggesting that the element is ready to give two electrons easily to form a di-positive ion however the third ionization energy is high which shows that it will not form tri-positive ion commonly.

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Answer:

b)

Explanation:

It shows the natrual proggresion of a story and helps blend the narrtive together.

4 0
3 years ago
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What is the temperature of 0.5 moles of water vapor that occupies 120 dm3 and applies a pressure of 15,000 Pa to its container?
MArishka [77]
Use the ideal gas law:

PV = nRT

so, T = PV / nR

n=0.5
V= 120 dm^3 = 120 L  (1 dm^3 = 1 L)
R = 1/12
P = 15,000 Pa =  0.147 atm     (1 pa = 9.86 10^{-6} )

Put the values:

T = PV / nR
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3 years ago
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3 0
3 years ago
1. the purpose of the aqueous solutions in a galvanic cell is to?
ludmilkaskok [199]

Answer:

1. The correct option is;

c. maintains charge balance in the cell

2. The correct option is;

c. +3.272 V

Explanation:

The aqueous solution in a galvanic cell is the electrolyte which is a ionic solution containing that permits the transfer of ions between the separated compartment of the galvanic cell such that the overall system is electrically neutral

Therefore, the aqueous solution maintains the charge balance in the cell

2. Here we have;

B₂ + 2e⁻ → 2B⁻ Ecell = 0.662 V

A⁺ + 1e⁻ → A Ecell = -1.305 V

Hence for the overall reaction, we have;

2A + B₂ → 2AB gives;

(0.662) - 2×(-1.305)  = +3.272 V.

4 0
3 years ago
a quantity of gas has a volume of 400.0 mL when confined under a pressure of 600.0mm Hg. what will be the new volume of the gas
Alex787 [66]

Answer:

1200 mL

Explanation:

Given data

  • Initial pressure (P₁): 600.0 mmHg
  • Initial volume (V₁): 400.0 mL
  • Final pressure (P₂): 200.0 mmHg
  • Final volume (V₂): ?

For a gaseous sample, there is an inverse relationship between the pressure and the volume. If we consider the gas as an ideal gas, we can find the final volume using Boyle's law.

P_1 \times V_1 = P_2 \times V_2\\V_2 = \frac{P_1 \times V_1}{P_2} = \frac{600.0mmHg \times 400.0mL}{200.0mmHg}=1200 mL

3 0
3 years ago
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