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Airida [17]
3 years ago
10

John dalton proposed a theory that all matter is made up of individuals particles which cannot be divided. what were those parti

cles?
Chemistry
1 answer:
juin [17]3 years ago
3 0
The particles are atoms, his theory is the atomic theory
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Answer this correctly, only sincere answers please. I really need help. I will do all I can to make someone answer this. Thanks!
Marrrta [24]

Answer:

See Explanation

Explanation:

Let us recall that;

[H^+] [OH^-] = 1 * 10^-14

Where;

[OH^-] = 1 x 10^-11

Then;

[H^+] = 1 * 10^-14/1 x 10^-11

[H^+] = 1 * 10^-3

pH = -log [H^+]

pH = -log(1 * 10^-3)

pH = 3

Also;

pH + pOH = 14

pOH = 14 - pH

pOH = 14 -3

pOH = 11

8 0
3 years ago
Imagine you are on a roller coaster. Imagine that you are riding a skateboard or running across a ball field. What are some clue
Alex787 [66]

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4 0
4 years ago
Acetone is a common solvent and has a density of 0.7899 g/mL. What volume of acetone, in mL, has a mass of 28.7 g?
Svet_ta [14]
Density = 0.7899 g/mL

mass = 28.7 g

Volume = ?

therefore:

D = m / V

0.7899 =  28.7 / V

V = 28.7 / 0.7899

V  = 36.333 mL




6 0
3 years ago
Read 2 more answers
How to separate sand from salt
IRINA_888 [86]
Put the salt and sand in some water.
the salt will not be visible but the sand will
now strain the the sand from the water
now boil the water and now the water will boil away and now you will just have salt left.
6 0
3 years ago
In a titration of 35.00 mL of 0.737 M H2SO4, __________ mL of a 0.827 M KOH solution is required for neutralization.
elena55 [62]

Answer:

In a titration of 35.00 mL of 0.737 M H₂SO₄, 62.4 mL of a 0.827 M KOH solution is required for neutralization.

Explanation:

The balanced reaction is

H₂SO₄  +  2 KOH  ⇒  2 H₂O  +  K₂SO₄

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction)  1 mole of H₂SO₄ is neutralized with 2 moles of KOH.

The molarity M being the number of moles of solute that are dissolved in a given volume, expressed as:

Molarity=\frac{number of moles}{volume}

in units of \frac{moles}{liter}

then the number of moles can be calculated as:

number of moles= molarity* volume

You have acid H₂SO₄

  • 35.00 mL= 0.035 L (being 1,000 mL= 1 L)
  • Molarity=  0.737 M

Then:

number of moles= 0.737 M* 0.035 L

number of moles= 0.0258

So you must neutralize 0.0258 moles of H₂SO₄. Now you can apply the following rule of three: if by stoichiometry 1 mole of H₂SO₄ are neutralized with 2 moles of KOH, 0.0258 moles of H₂SO₄ are neutralized with how many moles of KOH?

moles of KOH=\frac{0.0258moles of H_{2} SO_{4}*2 moles of KOH }{1mole of H_{2} SO_{4}}

moles of KOH= 0.0516

Then 0.0516 moles of KOH are needed. So you know:

  • Molarity= 0.827 M
  • number of moles= 0.0516
  • volume=?

Replacing in the definition of molarity:

0.827 M=\frac{0.0516 moles}{volume}

Solving:

volume=\frac{0.0516 moles}{0.827 M}

volume=0.0624 L= 62.4 mL

<u><em>In a titration of 35.00 mL of 0.737 M H₂SO₄, 62.4 mL of a 0.827 M KOH solution is required for neutralization.</em></u>

4 0
3 years ago
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