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SSSSS [86.1K]
3 years ago
10

What is the value of x in the equation x – y = 30, when y = 15? its not 45 tho

Mathematics
2 answers:
Charra [1.4K]3 years ago
7 0
-15 would be your answer a negative plus a negative the signs together would turn negative 15 to positive
Anton [14]3 years ago
5 0
It’s -15 because when you subtract 15 from 30 it turns out as 15 but then when you try doing +15-15 it comes out as 0, instead of adding positive 15, do negative because a negative times a negative is positive.
The answer would be -15-15=30

Hope this helps!!
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3. Six less than twice a number is 17. Which equation could be used to determine the
Usimov [2.4K]

Answer & Step-by-step explanation:

n represents our number. So, twice a number would be 2n because twice means multiply by two.

When the problem says 6 less, then it means 6 less than 2n. So, it would look like 2n-6.

FInally, the problem says that all of this equals 17 so 17 would be the result.

So, you answer is 2n-6 = 17. This is answer choice B.

6 0
3 years ago
You are a lifeguard and spot a drowning child 60 meters along the shore and 40 meters from the shore to the child. You run along
sukhopar [10]

Answer:

The lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

Step-by-step explanation:

This is a problem of optimization.

We have to minimize the time it takes for the lifeguard to reach the child.

The time can be calculated by dividing the distance by the speed for each section.

The distance in the shore and in the water depends on when the lifeguard gets in the water. We use the variable x to model this, as seen in the picture attached.

Then, the distance in the shore is d_b=x and the distance swimming can be calculated using the Pithagorean theorem:

d_s^2=(60-x)^2+40^2=60^2-120x+x^2+40^2=x^2-120x+5200\\\\d_s=\sqrt{x^2-120x+5200}

Then, the time (speed divided by distance) is:

t=d_b/v_b+d_s/v_s\\\\t=x/4+\sqrt{x^2-120x+5200}/1.1

To optimize this function we have to derive and equal to zero:

\dfrac{dt}{dx}=\dfrac{1}{4}+\dfrac{1}{1.1}(\dfrac{1}{2})\dfrac{2x-120}{\sqrt{x^2-120x+5200}} \\\\\\\dfrac{dt}{dx}=\dfrac{1}{4} +\dfrac{1}{1.1} \dfrac{x-60}{\sqrt{x^2-120x+5200}} =0\\\\\\  \dfrac{x-60}{\sqrt{x^2-120x+5200}} =\dfrac{1.1}{4}=\dfrac{2}{7}\\\\\\ x-60=\dfrac{2}{7}\sqrt{x^2-120x+5200}\\\\\\(x-60)^2=\dfrac{2^2}{7^2}(x^2-120x+5200)\\\\\\(x-60)^2=\dfrac{4}{49}[(x-60)^2+40^2]\\\\\\(1-4/49)(x-60)^2=4*40^2/49=6400/49\\\\(45/49)(x-60)^2=6400/49\\\\45(x-60)^2=6400\\\\

x

As d_b=x, the lifeguard should run across the shore a distance of 48.074 m before jumpng into the water in order to minimize the time to reach the child.

7 0
3 years ago
What constant term should be used to complete the square? x 2 - 5x + _____ = 7
amm1812
The quadratic equation in its generic form is:
 ax2 + bx + c
 To complete squares we must add the following term:
 (b / 2) ^ 2
 The equation is:
 ax2 + bx + c + (b / 2) ^ 2
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 x ^ 2 - 5x + (-5/2) ^ 2 = 7 + (-5/2) ^ 2
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 Answer:
 
A constant term should be used to complete the square is:
 
6.25
4 0
3 years ago
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r-ruslan [8.4K]
6.37864 kilo ... hopefully thats helpful!
6 0
3 years ago
Read 2 more answers
Explain how you can use your compass to construct one-fourth the length of a segment.​
kogti [31]

Answer:

You caluculate the value of the segment then multiply it by 1/4. After that you move the compass to match the radius of the segment

Step-by-step explanation:

Sorry if that didnt make sense

7 0
3 years ago
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