The maximum mortgage payment allowed for someone with an annual salary of $73.025 would be $2,190.75 per month, so the correct option is A.
<h2><u>How to determine the amount using the standard 28/36 guides?</u></h2>
To determine, using the standard 28/36 guidelines, what is the maximum mortgage payment allowed for someone with an annual salary of $73,025, the following calculation must be made:
- ((73025 x 36) / 100) / 12 = X
- (2,628,900 / 100) / 12 = X
- 26,289 / 12 = X
- 2,190.75 = X
Therefore, the maximum mortgage payment allowed for someone with an annual salary of $73.025 would be $2,190.75 per month.
Learn more about mortgages in brainly.com/question/20589209
For this case we have the following product:

We must use the distributive property correctly to solve the problem.
We have then:

Then, we must add similar terms.
We have then:
Answer:
The final product is given by:
option 2
1/3 ln(<em>x</em>) + ln(2) - ln(3) = 3
Recall that
, so
ln(<em>x</em> ¹ʹ³) + ln(2) - ln(3) = 3
Condense the left side by using sum and difference properties of logarithms:


Then
ln(2/3 <em>x</em> ¹ʹ³) = 3
Take the exponential of both sides; that is, write both sides as powers of the constant <em>e</em>. (I'm using exp(<em>x</em>) = <em>e</em> ˣ so I can write it all in one line.)
exp(ln(2/3 <em>x</em> ¹ʹ³)) = exp(3)
Now exp(ln(<em>x</em>)) = <em>x </em>for all <em>x</em>, so this simplifies to
2/3 <em>x</em> ¹ʹ³ = exp(3)
Now solve for <em>x</em>. Multiply both sides by 3/2 :
3/2 × 2/3 <em>x</em> ¹ʹ³ = 3/2 exp(3)
<em>x</em> ¹ʹ³ = 3/2 exp(3)
Raise both sides to the power of 3:
(<em>x</em> ¹ʹ³)³ = (3/2 exp(3))³
<em>x</em> = 3³/2³ exp(3×3)
<em>x</em> = 27/8 exp(9)
which is the same as
<em>x</em> = 27/8 <em>e</em> ⁹
Answer:
3,600−−−−−√ is a rational number.I guess