Actually Rb or Rubidium in zero state has the following
electron configuration:
<span>1s22s2</span><span>2p6</span><span>3s2</span><span>3p63d10</span><span>4s2</span><span>4p65s1</span>
However we can see that the ion has a 1 positive charge,
which means that it lacks 1 electron, therefore the answer from the choices is:
<span>d.
rb+: 1s22s22p63s23p64s23d104p6</span>
Answer:
4.3043x10^24
Explanation:
Atoms(H) = (3.575 mol H2S/1)(2 mol H/1mol H2S)(6.02x10^23/1molH)
Simple stoicheometry problem. Sorry for taking so long, took Chem sophomore year, its been a while
Answer:
Your notation is a bit confusing, let me write it more clearly.
Explanation:
( Temperature in °F − 32) × 5/9 = Temperature in °C
The answer is hydrogen. the first element in the periodic table.
In order to find the percentage change in mass, you must d<span>ivide </span>Change in Mass<span> by Initial </span>Mass<span>. After that, you divide the </span>change in mass<span> by the initial </span>mass<span> of your substance.
This calculation shows what proportion of the initial </span>mass<span> changed. To find the </span>percent change<span>, simply multiply this number by 100</span>
