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Salsk061 [2.6K]
3 years ago
13

In 1993 the Minnesota Department of Health set a health risk limit for chloroform in groundwater of 60.0 g/L Suppose an analytic

al chemist receives a sample of groundwater with a measured volume of 79.0 mL. Calculate the maximum mass in milligrams of chloroform which the chemist could measure in this sample and still certify that the groundwater from which it came met Minnesota Department of Health standards. Be sure your answer has the correct number of significant digits. mg
Chemistry
1 answer:
tangare [24]3 years ago
6 0

Answer:

4.74 × 10³ mg

Explanation:

Given data

  • Health risk limit for chloroform in groundwater: 60.0 g/L
  • Volume of the sample of groundwater: 79.0 mL = 79.0 × 10⁻³ L

The maximum mass of chloroform that there could be in the sample of groundwater to meet the standards are:

79.0 × 10⁻³ L × 60.0 g/L = 4.74 g

1 gram is equal to 10³ milligrams. Then,

4.74 g × (10³ mg/1 g) = 4.74 × 10³ mg

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How much heat is needed to raise the temperature of water with mass of 27.0 g at 20.0°C to 45.0°C?
ohaa [14]

Answer:

2835 J

Explanation:

Take the specific heat capacity of water as 4.2 J/ g°C.

Energy (heat) = mass x specific heat capacity x change in temperature

(E= mcΔT)

E = 27 x 4.2 x (45-20)

E = 2835 J

7 0
4 years ago
The maximum number of electrons that are possible at a given energy level depends on the number of ____ at the energy level.
VMariaS [17]

Answer:

  • <u><em>     orbitals      </em></u>

Explanation:

Each orbital may contain a maximum of two electrons.

The energy level is the principal quantum number: 1, 2, 3, 4, 5, 6, 7.

The principal quantum number limits the kind of orbital (ℓ ) and the number of orbitals (mℓ ).

I. Principal quantum number, n = 1

  Angular or orbital quantum number : ℓ = 0 ⇒ ortibal s

  Magnetic quantum number:  mℓ = 0

                                 ⇒ number of orbitals 1 ⇒ number of electrons: 2

                         

II. Principal quantun number, n = 2

  Angular or orbital quantum number : ℓ = 0 and 1 ⇒ ortibal s and p

  Magnetic quantum number:  

                                            for ℓ:  mℓ = 0: 1 s ortibal

                                            for ℓ = 1: mℓ = -1, 0, and +1:  3 p ortitals

                                 ⇒ number of orbitals 4 ⇒ number of electrons: 8

III. Principal quantun number, n = 3

    Angular or orbital quantum number : ℓ = 0, 1, and 2 ⇒ ortibal s, p and d

    Magnetic quantum number:  

                                            for ℓ:  mℓ = 0: 1 s ortibal

                                            for ℓ = 1: mℓ = -1, 0, and +1:  3 p ortitals

                                            for ℓ = 2: mℓ = -2, -1, 0, +1, and +2:  5 d ortitals

                                 ⇒ number of orbitals 9 ⇒ number of electrons: 18

IV. Principal quantun number, n = 4

    Angular or orbital quantum number : ℓ = 0, 1, 2, and 3 ⇒ ortibal s, p, d and f

    Magnetic quantum number:  

                                            for ℓ:  mℓ = 0: 1 s ortibal

                                            for ℓ = 1: mℓ = -1, 0, and +1:  3 p ortitals

                                            for ℓ = 2: mℓ = -2, -1, 0, +1, and +2:  5 d ortitals

                                            for ℓ = 3: mℓ = ±3, ±2, ±1, and 0: 7 f ortitals

                                 ⇒ number of orbitals 16 ⇒ number of electrons: 32.

Thus, you have:

energy level, n    maximum number of     maximum number of

                             orbitals                           electrons

      1                           1                                      2

      2                          4                                     8

      3                          9                                    18

      4                          16                                   32

Those numbers follow a rule: n² and 2n². You can verify that the previous numbers are in accordance with those formulas.

3 0
3 years ago
Cuando realizamos la "Estructura de
sergeinik [125]

Answer:

Electrones de valencia.

Explanation:

¡Hola!

En este caso, dado en química se conocen las estructuras de Lewis como representaciones gráficas de como los elementos están enlazados entre sí, debemos tener en cuenta que estos enlaces se forman entre los electrones de valenciam, los cuales son utilizados para su representación. Se sabe que los electrones de valencia son representados con puntos alrededor del elemento a través de puntos que se unen entre sí y son el número de electrons en la capa más externa de los elementos en cuestión; por ejemplo, cloro tiene 7 electrones de valencia, azufre tiene 6, hidrogeno 1, carbono 4 y así sucesivamente.

¡Saludos!

3 0
3 years ago
Are eye drops a base or acid???
gregori [183]

base

bye hope you have a good day

3 0
4 years ago
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baherus [9]

Answer:

D, high in iron content

Explanation:

6 0
3 years ago
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