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Pavlova-9 [17]
3 years ago
8

ANSWER PLS ASAP Fireworks are an example of a amount of energy being

Chemistry
1 answer:
Georgia [21]3 years ago
3 0

Answer:

large, released

Explanation:

As we know, fireworks contain l o t s of energy, even before the burst of colors release. So i think choice 3 is the answer.

i hope this helps :)

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In which layer of the atmosphere can you find meteors?
asambeis [7]
The answer would be d :)
5 0
2 years ago
A typical aspirin tablet contains 327 mg of acetylsalicylic acid, HC9H7O4. Calculate the pH of a solution that is prepared by di
yawa3891 [41]

Answer:

2.8

Explanation:

First, we will calculate the molarity of the acetylsalicylic acid solution.

M = mass of solute (g) / molar mass of solute × volume of solution (L)

M = 0.327 g / 180.158 g/mol × 0.237 L

M = 7.66 × 10⁻³ M

For a weak acid such as acetylsalicylic acid, we can find the concentration of H⁺ using the following expression.

[H⁺] = √(Ca × Ka)

where,

Ca: concentration of the acid

Ka: acid dissociation constant

[H⁺] = √(7.66 × 10⁻³ × 3.3 × 10⁻⁴)

[H⁺] = 1.6 × 10⁻³ M

The pH is:

pH = -log [H⁺]

pH = -log 1.6 × 10⁻³ = 2.8

6 0
3 years ago
The mass of water in a single popcorn kernel was found to be 0.905 grams after it popped at a temperature of 175 °C. Using the i
Rus_ich [418]

Answer:

0.583 kilojoules

Explanation:

The amount of heat required to pop a single kernel can be calculated using the formula as follows:

Q = m × c × ∆T

Where;

Q = amount of heat (J)

m = mass of water (g)

c = specific heat capacity of water (4.184 J/g°C)

∆T = change in temperature

From the given information, m = 0.905 g, initial temperature (room temperature) = 21°C , final temperature = 175°C, Q = ?

Q = m × c × ∆T

Q = 0.905 × 4.184 × (175°C - 21°C)

Q = 3.786 × 154

Q = 583.044 Joules

In kilojoules i.e. we divide by 1000, the amount of heat is:

= 583.04/1000

= 0.583 kilojoules

8 0
3 years ago
Elements consist of tiny particles called
Nutka1998 [239]
The answer is atoms good luck
4 0
2 years ago
Calculate the freezing point of a solution containing 5. 0 grams of kcl and 550. 0 grams of water. the molal-freezing-point-depr
lutik1710 [3]

The freezing point of a solution containing 5. 0 grams of KCl and 550.0 grams of water is  - 0.45°C

Using the equation,

ΔT_{f} = iK_{f}m

where:

ΔT_{f} = change in freezing point (unknown)

i = Van't Hoff factor

K_{f} = freezing point depression constant

m = molal concentration of the solution

Molality is expressed as the number of moles of the solute per kilogram of the solvent.

Molal concentration is as follows;

MM KCl = 74.55 g/mol

molal concentration = \frac{5.0g*\frac{1mol}{74.55g} }{550.0g*\frac{1kg}{1000g} }

molal concentration = 0.1219m

Now, putting in the values to the equtaion ΔT_{f} = iK_{f}m we get,

ΔT_{f} = 2 × 1.86 × 0.1219

ΔT_{f} = 0.4536°C

So, ΔT_{f} of solution is,

ΔT_{f_{solution} } = 0.00°C - 0.45°C

ΔT_{f_{solution} } =  - 0.45°C

Therefore,freezing point of a solution containing 5. 0 grams of KCl and 550.0 grams of water is  - 0.45°C

Learn more about freezing point here;

brainly.com/question/3121416

#SPJ4

7 0
1 year ago
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