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mrs_skeptik [129]
4 years ago
9

I NEED HELP PLEASE, THANKS! :)

Mathematics
1 answer:
Varvara68 [4.7K]4 years ago
8 0

Answer:

  33\frac{1}{3}

Step-by-step explanation:

This is a straightforward evaluation of a definite integral.

  \displaystyle\int_1^5{x^2-x+1}\,dx=\left.\dfrac{x^3}{3}-\dfrac{x^2}{2}+x\right|_1^5=\dfrac{5^3-1^3}{3}-\dfrac{5^2-1^2}{2}+(5-1)\\\\=41\frac{1}{3}-12+4=\boxed{33\frac{1}{3}}

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Work Shown:

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Step-by-step explanation:

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