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Klio2033 [76]
3 years ago
13

Someone please help. Describe how electric potential energy, kinetic energy, and work change when two charges of opposite sign a

re placed near each other.
Physics
1 answer:
erik [133]3 years ago
5 0

Answer:

The answer is based on the conservation of energy law; something you should really understand by now.  

For convenience we can hold one of the two charges still; it becomes the frame of reference. And everything we say is in reference to the designated static charge, call it Q.  

So the moving charge, call it q, has total energy TE = PE. It's all potential energy as we start with q not moving.  

It has potential energy because in order to separate q from Q, we had to do work, add energy, on q. And from the COE law, that work added is converted into PE.  

It's a bit like lifting something off the ground. That's work and it becomes GPE. So there's some work, in separating the two charges in the first place.  

But there's more.  

Now we let q go. As opposites attract, q is pulled to Q. And that force from Q is working on q, force over distance. Which means the potential energy q started with is being converted into kinetic energy. q is accelerating and picking up speed.  

And there's more work, done by the EMF on charge q. That converts the PE into KE and the q charge smashes into Q with some kinetic energy.

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Snezhnost [94]

Answer:

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6 0
3 years ago
A piano tuner stretches a steel piano wire with a tension of 1070 N . The wire is 0.400 m long and has a mass of 4.00 g . A. Wha
pychu [463]

A. 409 Hz

The fundamental frequency of a string is given by:

f_1=\frac{1}{2L}\sqrt{\frac{T}{m/L}}

where

L is the length of the wire

T is the tension in the wire

m is the mass of the wire

For the piano wire in this problem,

L = 0.400 m

T = 1070 N

m = 4.00 g = 0.004 kg

So the fundamental frequency is

f_1=\frac{1}{2(0.400)}\sqrt{\frac{1070}{(0.004)/(0.400)}}=409 Hz

B. 24

For this part, we need to analyze the different harmonics of the piano wire. The nth-harmonic of a string is given by

f_n = nf_1

where f_1 is the fundamental frequency.

Here in this case

f_1 = 409 Hz

A person is capable to hear frequencies up to

f = 1.00 \cdot 10^4 Hz

So the highest harmonics that can be heard by a human can be found as follows:

f=nf_1\\n= \frac{f}{f_1}=\frac{1.00\cdot 10^4}{409}=24.5 \sim 24

8 0
3 years ago
What is the resultant of the vecotors shown?
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D, I believe would be the first minus the second vector.

To solve this I named the first vector as A and the second as B.

So... vector A - B = resultant

or A + (-B)

A negative indicates a direction of a vector so if we flip the direction the other way we have the first vector (A) pointing vertically upwards and then vector B pointing to the west.

Now we have to use the head to tail method, meaning that the head of the first vector has to connect with the tail of the other vector added.

So we should have something like this

(-B)  < -  -  - -  ^

                      |

                      |  (A)

                      |

To add these two vectors, technically A - B, draw a line from the tail of A to the head of -B which would look like image D.

Hope this helped!

3 0
4 years ago
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Explanation:

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It can be more relevant to the person's speed when she walks wading through the water or the person walks through the sand then the person feels resistance in the sand or in water which reduces her overall speed.

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yKpoI14uk [10]
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