<span>Basically just divide the change in position by the change in time. </span>
A collision from above such as a meteor and an increase in volcano activity.
Let the distance between the towns be d and the speed of the air be s.
distance = speed * time
convert the minutes time into hours.
When flying into the wind, ground speed will be air speed MINUS wind speed, hence the against the wind trip is described by:
d
s−15
=
7
3
return trip is then :
d
s+15
=
7
5
Cross-multiplying both we get the two-variable system:
3d=7∗(s−15)5d=7∗(s+15)
3d=7s−1055d=7s+105
subtract first equation from second equation we get
2d=210d=105km
Substitute the value of d in the above equations for s.
5∗105=7s+1057s=420s=60km/hr
Answer:
D.amplifying sound vibrations from the eardrum
this is correct
- initial velocity=u=24m/s
- Acceleration=a=4m/s^2
- Distance=s=96m
- Final velocity=v
Using 3rd equation of kinematics
