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2 years ago

A person standing waist-deep in a swimming pool appears to have short legs because of light

Physics

1 answer:

Rama09 [41]2 years ago

8 0

Answer:

Explanation:

Refraction :)

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In the picture at left. The launch height is 10m ball B mass 5kg has a launch velocity of 12 m/s and ball A mass 8 kg has a laun

Hitman42 [59]

Answer:

Explanation:

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3 years ago

What is NOT a raw minteral used in photosyntheisis

Yuliya22 [10]

The photosynthesis equation is :

H2O + CO2 + sunlight (energy) > C6H12O6 + O2

So water (H2O) and carbon dioxide (CO2) are the raw materials need for photosynthesis.

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3 years ago

Mga peymos d nang papallow back yan un follow ko na kayu mga bubu

melisa1 [442]

Answer:

<h2> Ah Filipino ka rin?</h2>

Explanation:

7 0

2 years ago

Read 2 more answers

Early cameras were little more than a box with a pinhole on the side opposite the film. (a) What angular resolution would you ex

ollegr [7]

Answer:

angular resolution = 0.07270° = 1.269 × $10^{-3}$ rad

greatest distance from the camera = 118.20 m = 0.118 km

Explanation:

given data

diameter = 0.50 mm = 0.5 × $10^{-3}$ m

distance apart = 15 cm = 15× $10^{-2}$ m

wavelength λ = 520 nm = 520 × $10^{-9}$ m

to find out

angular resolution and greatest distance from the camera

solution

first we expression here angular resolution that is

sin θ = $\frac{1.22* \lambda }{D}$ .......................1

put here value λ is wavelength and d is diameter

we get

sin θ = $\frac{1.22*520*10^{-9}}{0.5*10^{-3}}$

θ = 0.07270° = 1.269 × $10^{-3}$ rad

and

distance from camera is calculate here as

θ = $\frac{I}{r}$ .................2

I = $\frac{15*10^{-2}}{1.269*10^{-3}}$

I = 118.20 m = 0.118 km

3 0

3 years ago

The speed of a certain proton is 350 km/s. If the uncertainty in its momentum is 0.100%, what is the necessary uncertainty in it

Evgesh-ka [11]

Answer:

$\Delta x = 1.807 \times 10^{-10}m$

Explanation:

mass of proton, m = 1.67 x 10^-27 kg

speed of proton, v = 350 km/s = 350,000 m/s

Momentum of proton, p = mass x speed

p = 1.67 x 10^-27 x 350000 = 5.845 x 10^-22 kg m /s

uncertainty in momentum, Δp = 0.1 % of p

Δp = $\frac{0.1\times 5.845 \times 10^{-22}}{100}=5.845 \times 10^{-25}$

According to the principle

$\Delta x\times \Delta p \geq \frac{h}{2\pi }$

where, Δx be the uncertainty in position

$\Delta x\times 5.845 \times 10^{-25}= \frac{6.634 \times 10^{-34}}{2\times 3.14}$

$\Delta x = 1.807 \times 10^{-10}m$

5 0

2 years ago