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1 year ago

photon strikes the surface of tungsten and an electron is emitted. what is the maximum possible speed of the electron?

Physics

1 answer:

zalisa [80]1 year ago

3 0

Answer: The maximum possible speed v is √2( hν - Ф ) / m

Explanation: You could be referring to the provided explanation, despite the fact that the question isn't comprehensive. When a photon collides with the surface of any metal, it transmits all of its energy to the electron in the atom. The collision causes the electron to travel with a certain amount of kinetic energy. This is referred to as the photoelectric effect. The maximum kinetic energy is calculated using Einstein's equation for the photoelectric effect:

K.E. = hν - Ф

½ mv² = hν - Ф

Hence the maximum possible speed is:

v = √2( hν - Ф ) / m

For more information on the photoelectric effect refer to this link: brainly.com/question/25027428

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1 year ago

One car travels 56 meters due east in 2.0 seconds, and a second car travels 84 meters due west in 3.0 seconds. During their peri

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3 years ago

You lift a 25-kg child 0.80 m, slowly carry him 10 m to the playroom, and finally set him back down 0.80 m onto the playroom flo

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To solve this problem we will apply the work theorem which is expressed as the force applied to displace a body. Considering that body strength is equivalent to weight, we will make the following considerations

$\text{Mass of the child} = m = 25kg$

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$\text{Height lifted} = h = 0.80m (Upward)$

Work done to upward the object

$W = mgh$

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Horizontal Force applied while carrying 10m,

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3 years ago

A circuit component that is a composed of a semiconductor layer sandwiched between two other semiconductor layers is a(n)?

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Explanation:

It's a transistor. Hope that helps!

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2 years ago

Read 2 more answers

When two resistors are wired in series with a 12 V battery, the current through the battery is 0.33 A. When they are wired in pa

Tcecarenko [31]

Answer:

If R₂=25.78 ohm, then R₁=10.58 ohm

If R₂=10.57 then R₁=25.79 ohm

Explanation:

R₁ = Resistance of first resistor

R₂ = Resistance of second resistor

V = Voltage of battery = 12 V

I = Current = 0.33 A (series)

I = Current = 1.6 A (parallel)

In series

$\text{Equivalent resistance}=R_{eq}=R_1+R_2\\\text {From Ohm's law}\\V=IR_{eq}\\\Rightarrow R_{eq}=\frac{12}{0.33}\\\Rightarrow R_1+R_2=36.36\\ Also\ R_1=36.36-R_2$

In parallel

$\text{Equivalent resistance}=\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}\\\Rightarrow {R_{eq}=\frac{R_1R_2}{R_1+R_2}$

$\text {From Ohm's law}\\V=IR_{eq}\\\Rightarrow R_{eq}=\frac{12}{1.6}\\\Rightarrow \frac{R_1R_2}{R_1+R_2}=7.5\\\Rightarrow \frac{R_1R_2}{36.36}=7.5\\\Rightarrow R_1R_2=272.72\\\Rightarrow(36.36-R_2)R_2=272.72\\\Rightarrow R_2^2-36.36R_2+272.72=0$

Solving the above quadratic equation

$\Rightarrow R_2=\frac{36.36\pm \sqrt{36.36^2-4\times 272.72}}{2}$

$\Rightarrow R_2=25.78\ or\ 10.57\\ If\ R_2=25.78\ then\ R_1=36.36-25.78=10.58\ \Omega\\ If\ R_2=10.57\ then\ R_1=36.36-10.57=25.79\Omega$

∴ If R₂=25.78 ohm, then R₁=10.58 ohm

If R₂=10.57 then R₁=25.79 ohm

3 0

3 years ago